Two-prover entangled games are NP hard Anand Natarajan (MIT) - - PowerPoint PPT Presentation

two prover entangled games are np hard
SMART_READER_LITE
LIVE PREVIEW

Two-prover entangled games are NP hard Anand Natarajan (MIT) - - PowerPoint PPT Presentation

Two-prover entangled games are NP hard Anand Natarajan (MIT) Thomas Vidick (Caltech) arXiv:1710.03062 Interactive proofs MIP IP Completeness: If YES, prover can convince verifier with Pr c (e.g. 2/3) Soundness : If NO, prover cannot


slide-1
SLIDE 1

Two-prover entangled games are NP hard

Anand Natarajan (MIT) Thomas Vidick (Caltech) arXiv:1710.03062

slide-2
SLIDE 2

Interactive proofs

MIP = PSPACE [Shamir ‘90] IP = NEXP [BFL ‘91]

Completeness: If YES, prover can convince verifier with Pr ≥ c (e.g. 2/3) Soundness: If NO, prover cannot convince verifier with Pr ≥ s (e.g. 1/3)

slide-3
SLIDE 3

Interactive proofs

= PSPACE [Shamir ‘90] IP

Completeness: If YES, prover can convince verifier with Pr ≥ c (e.g. 2/3) Soundness: If NO, prover cannot convince verifier with Pr ≥ s (e.g. 1/3)

MIP (log n bit messages) = NP [ALMSS’98,AS’98]

slide-4
SLIDE 4

|Ψ⟩

Quantum interactive proofs

MIP*

(c. verifier, c. messages, q. provers)

Still = PSPACE ! [JJUW’09] QIP:

(q. verifier, q. messages)

What about a quantum verifier, or quantum messages?

How powerful is it?

slide-5
SLIDE 5

Entangled provers

  • Entanglement makes provers more

powerful

  • [Bell64, CHSH68]: T

wo-prover, one round protocol

– Best classical psuccess = 0.75 – With entanglement (1 EPR pair) psuccess ≈ 0.85

  • This can hurt soundness!
  • [CHTW04]: ⊕MIP*(2) ⊆ PSPACE

– ⊕MIP(2) = MIP = NEXP [Håstad’01] – Based on SDP characterization of quantum strategies due to Tsirelson

slide-6
SLIDE 6

|Ψ⟩

Quantum interactive proofs

MIP*

(c. verifier, c. messages, q. provers)

Still = PSPACE ! [JJUW’09] QIP:

(q. verifier, q. messages)

What about a quantum verifier, or quantum messages?

Contains NEXP [IV’12] ⊕MIP*(3) contains NEXP [Vidick’13]

slide-7
SLIDE 7

Two vs three provers

  • Classically: reduce any MIP protocol to 2

provers using oracularization

  • Quantumly: no general prover reduction

known

– Monogamy of entanglement: if Alice is maximally entangled with Bob, must share zero entanglement with Charlie! – [T

  • ner’09] shows 3-prover versions of CHSH,
  • dd-cycle game have lower entangled psuccess
slide-8
SLIDE 8

|Ψ⟩

Results

MIP*

(c. verifier, c. messages, q. provers)

Still = PSPACE ! [JJUW’09] QIP:

(q. verifier, q. messages)

What about a quantum verifier, or quantum messages?

This work:

  • Contains NEXP
  • For log(n)-bit

messages, contains NP

slide-9
SLIDE 9

Low-degree test

  • Encode an NP-proof as a low-degree

polynomial g: !q

m → !q

– qm =Θ(n)

  • Let x ∈ !q

m be random point,

s ⊆ !q

m random plane containing x

– Ask Alice for g(x) – Ask Bob for g|s as polynomial – Check that g|s (x) = g(x)

  • Thm [RS’97]:

If pass with prob ≥ 1- ε, agree with some low-degree g on ≥ 1 –O(εc) fraction of points

s x

slide-10
SLIDE 10

Soundness against entangled provers

  • Entangled strategy:

– Shared state |Ψ⟩ – Points measurements: Ax

a ≥ 0, Σa Ax a = Id

– Planes measurements: Bs

h ≥ 0, Σh Bs h = Id

  • Thm: If pass with prob ≥ 1- ε,

exists measurement {Mg} s.t. ⟨Ψ| Mg ⊗ Ax

g(x)|Ψ⟩ ≥ 1- O(εc)

s x

slide-11
SLIDE 11

Induction

  • Hypothesis: If pass test on !q

m-1 with

prob ≥ 1- ε, exists measurement {Mg} with g: !q

m-1 → !q s.t. ⟨Ψ| Mg ⊗ Ax g(x)|Ψ⟩ ≥ 1- δ

  • Goal: If pass test on !q

m with prob ≥ 1- ε,

exists measurement Mg with g: !q

m → !q s.t.

⟨Ψ| Mg ⊗ Ax

g(x)|Ψ⟩ ≥ 1- δ

slide-12
SLIDE 12

Induction

  • Hypothesis: If pass test on !q

m-1 with prob ≥

1- ε, exists measurement {Mg} with g: !q

m-1 →

!q s.t. ⟨Ψ| Mg ⊗ Ax

g(x)|Ψ⟩ ≥ 1- δ

  • Implies: for most dim-(m-1) subspaces s,

exists {Ms

g} that is δ’-consistent with {Ax a}

  • Goal: If pass test on !q

m with prob ≥ 1- ε,

exists measurement Mg with g: !q

m → !q s.t.

⟨Ψ| Mg ⊗ Ax

g(x)|Ψ⟩ ≥ 1- δ’’

  • Problem: δ’’ > δ’ > δ!
slide-13
SLIDE 13

Induction with self- improvement

  • Hypothesis: If pass test on !q

m-1 with

prob ≥ 1- ε, exists measurement {Mg} with g: !q

m-1 → !q s.t. ⟨Ψ| Mg ⊗ Ax g(x)|Ψ⟩ ≥ 1- δ

  • Implies: for most dim-(m-1) subspaces

s ⊆ !q

m, exists {Ms g} that is δ-consistent with

{Ax

a}

  • Goal: If pass test on !q

m with prob ≥ 1- ε,

exists measurement Mg with g: !q

m → !q s.t.

⟨Ψ| Mg ⊗ Ax

g(x)|Ψ⟩ ≥ 1- δ

slide-14
SLIDE 14

Self-improvement

  • Given:

– {Ax

a} ε-”globally consistent”

– {Qg} η-consistent with {Ax

a}

Ex Σg Σa≠g(x) ⟨Ψ| Qg ⊗ Ax

a|Ψ⟩ ≤ η

  • Construct improved {Sg}

– ε1/2-consistent with {Ax

a}

Ex Σg Σa≠g(x) ⟨Ψ| Sg ⊗ Ax

a|Ψ⟩ ≤ ε1/2

– η’ := 1 – ε1/2 – η complete Σg ⟨Ψ| Sg ⊗ Id |Ψ⟩ ≥ η’

y x {Ax

a}

{Ay

a}

{Sg}

slide-15
SLIDE 15

Self-improvement: SDP

  • Ag := Ex[Ax

g(x)]

– Note: Σg Ag may not be ≤ Id

  • SDP (“majority vote”)

max Σg Tr[Tg Ag] s.t.Tg ≥ 0, Σg Tg ≥ Id

  • Qg is primal feasible, so SDP

value ≥ 1 - η

  • Define

Sg := Ex Ax

g(x) Tg Ax g(x)

y x {Ax

a}

{Ay

a}

{Sg}

slide-16
SLIDE 16

Self-improvement: consistency

  • Sg := Ex Ax

g(x) Tg Ax g(x)

  • Ex Σg Σa≠g(x) ⟨Ψ| Sg ⊗ Ax

a|Ψ⟩

= Ex Ey Σg Σa≠g(x) ⟨Ψ| Ay

g(y) Tg Ay g(y) ⊗ Ax a|Ψ⟩

≤ O(ε1/2)

slide-17
SLIDE 17

Self-improvement: completeness

  • Ag := Ex[Ax

g(x)]

Sg = Ex Ax

g(x) Tg Ax g(x)

  • Dual SDP

min Tr[Z] s.t. Z ≥ Ag, Z ≥ 0

  • Complementary

slackness: Tg Ag = Tg Z Σg ⟨Ψ| Sg ⊗ Id|Ψ⟩ ≈ Σg ⟨Ψ| Tg Ag ⊗ Id |Ψ⟩ = Σg ⟨Ψ| Tg Z ⊗ Id |Ψ⟩ = ⟨Ψ| Z ⊗ Id |Ψ⟩ ≥ 1- η’

slide-18
SLIDE 18

Applications and future work

  • Superclassical hardness results

– In [NV’18] improved to QMA-hardness – [Ji’17,FJVY’18] for small soundness

  • Entanglement-sound tests for locally testable

codes?

  • Non-signaling soundness?
  • Prover reduction for MIP*?
slide-19
SLIDE 19

THE END

arXiv:1710.03062