Thinking Like a Chemist About Acids and Bases Part IV UNIT 6 DAY 8 - - PowerPoint PPT Presentation

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Thinking Like a Chemist About Acids and Bases Part IV UNIT 6 DAY 8 - - PowerPoint PPT Presentation

Thinking Like a Chemist About Acids and Bases Part IV UNIT 6 DAY 8 Wednesday, February 26 What are we going to learn today? Buffers Explore Acid Base Titrations Poll: Clicker Question Fully describe: Weak Base + Strong Acid reaction


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Thinking Like a Chemist About Acids and Bases Part IV UNIT 6 DAY 8 Wednesday, February 26

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What are we going to learn today?

Buffers Explore Acid – Base Titrations

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Fully describe: Weak Base + Strong Acid reaction with resulting salt solution

Write the chemical reaction and calculate the pH when a 200 mL 0.1 M solution of ammonia is mixed with a 100 mL 0.1 M solution of hydrochloric acid. Kb for NH3 = 1.8 x 10-5 Before you do the calculation you should be able to predict if the resulting solution would be: A) Neutral B) Basic C)Acidic

Poll: Clicker Question

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Fully describe: Weak Base + Strong Acid reaction with resulting salt solution

Write the chemical reaction and calculate the pH when a 200 mL 0.1 M solution of ammonia is mixed with a 100 mL 0.1 M solution of hydrochloric acid. Kb for NH3 = 1.8 x 10-5 What is the pH?

  • A. 4.7
  • B. 9.3
  • C. 7
  • D. 3.6
  • E. 10.4

Poll: Clicker Question

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Add a little NaOH to pure water and see what happens! Add a little NaOH to a 1:1 mixture of acetic acid and sodium acetate and see what happens! What is the difference?

Look at a DEMO

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Write down the neutralization reaction for the demo

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Because the pH changed very little it is called a buffer solution.

Buffer- a solution in which the pH resists change when a strong acid or base is added Buffers can be acidic Buffers can be basic

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Because the pH changed very little it is called a buffer solution.

What happens if we keep adding NaOH to the solution…..

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Calculate the pH of buffer solution

  • 1 mole CH3COOH and 1 mole NaCH3COO in 1

L solution.

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Derive a shortcut formula

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initial conjugate base initial weak acid

When the initial acid and base are similar in concentration then the pH is close to the pKa For the pH to be 1 unit different than the pKa the difference in concentrations must be at least 10 X!

Henderson-Hasselbach

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  • A. slightly less than 3.18
  • B. 3.18
  • C. slightly more than 3.18

The pKa of HF is 3.18. What is the pH of solution

  • f 100 mL of 0.1 M HF and 100 mL of a 0.2 M

NaF?

Poll: Clicker Question

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Calculate the pH of a buffer system Calculate the pH of a buffer solution that is 0.15 M HNO2(aq) and 0.2 M NaNO2(aq) .

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Compare the two solutions

0.15 M HNO2(aq) 0.2 M NaNO2 (aq) pH = 3.94 0.015 M HNO2(aq) 0.02 M NaNO2 (aq) pH = 3.94 Any important differences between the two?

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  • You have a buffer solution containing acetic

acid and acetate ion. You adjust the pH to be 3.75. Which is present in the higher concentration: the protonated or deprotonated molecule?

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Calculating pH of a Buffer

  • 1. Look at what you are given, and think like a chemist.
  • 2. Is the buffer acidic or basic?
  • 3. Has additional acid or base been added to the buffer system?
  • 4. If so, complete the neutralization reaction, and calculate the

concentration of the buffer components

  • 5. Choose the correct version of the Henderson-Hasselbalch

equation.

  • 6. Using the equation, calculate the pH.

All this is on website. Two worksheets for practice. Practice makes perfect.

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What is the purpose of a buffer?

Poll: Clicker Question

One needs to keep an unusual microbial species alive in a laboratory setting. The microbe survives best in an alkaline environment with a pH > 9. The best choice of a buffering system would be equal molar amounts of: A) C2H5NH2, C2H5NH3

+, Kb = 5.6 x 10-4

B) C6H5NH2, C6H5NH3

+, Kb = 3.8 x 10-10

C) HClO2, ClO2

  • , Ka = 1.2 x 10-2

D) HOCl, OCl-, Ka = 3.5 x 10-8

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Choosing a Buffer

The best situation is: Relatively high concentration of conjugate acid-base partners. One to one molar concentration will buffer against both added acid and added base. One to one molar concentration – buffer will have a pH = pKa. PRACTICE! HOMEWORK & WORKSHEETS!

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What did we learn today?

Weak acids or bases have limited ionization in the presence of a common ion. Substantial amounts of conjugate acid base pairs, together in solution resist change in pH.

  • This effect is called buffering.
  • When [HA] = [A-], the pKa = pH of that solution.
  • When [B] = [BH+], the pKb = pOH of that solution.
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IMPORTANT INFORMATION HW07 LM22 – Titrations LM 23 Exam 2 – Tuesday, March, 4th - Rooms TBA

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Learning Outcomes

Understand the concept of a buffer, buffer capacity and buffering range. Calculate the pH of a buffer solution. Show mastery of the Henderson-Hasselbalch equation Calculate the pH of a buffer solution after the addition of a strong acid or strong base.