Quantum dark solitons in the one- dimensional Bose gas
Humboldt Kolleg – Controlling quantum matter: from ultracold atoms to solids– July 2018
Quantum dark solitons in the one- dimensional Bose gas Joachim - - PowerPoint PPT Presentation
Quantum dark solitons in the one- dimensional Bose gas Joachim Brand Humboldt Kolleg Controlling quantum matter: from ultracold atoms to solids July 2018 Sophie S. Shamailov Solitons Water Optics BEC Coupled Pedula Tikhonenko et al.
Humboldt Kolleg – Controlling quantum matter: from ultracold atoms to solids– July 2018
3 credit: Alex Kasman Tikhonenko et al. (1996)
Optics
Sengstock group (2008)
Water Coupled Pedula BEC
Hamburg Experiment: Becker et al. (2008)
Theory:
Experiment:
Movie credits: Nick Parker
Dark and grey soliton solution (g>0): Tsuzuki, JLTP (1971)
Kivshar, Luther-Davis (1998)
Number density
Phase
Ptot = ~
N
X
j=1
kj, Etot = ~2 2m
N
X
j=1
k2
j.
kj -
N
x k a k x exp ,
i i S N i i i
⟨{ } { }⟩ ( )
( ) ( )
⎛ ⎝ ⎜ ⎞ ⎠ ⎟
| =
∈
P
P P
Ij
l
H = − ~2 2m
N
X
j=1
d2 dx2
j
+ g X
hi,ji
δ (xi − xj)
Momentum Energy Here for Tonks-Girardeau gas, γ = ∞, N=15 Lieb’s type II elementary excitations Umklapp excitation (ring current)
P 2π~n
Experimental probe
factor Fabbri et al. (2015)
−1 1 2 3 4 5
P ¯ hn0 2m ¯ h2n2
0(E − Eg)
π/2 π 3π/2 2π
−1 1 2 3 4 5
P ¯ hn0 2m ¯ h2n2
0(E − Eg)
π/2 π 3π/2 2π
Fialko, Delattre, JB, Kolovsky (2012) Shamailov, Brand, arXiv:1805.07856
p,q
q
p hq, yr|ˆ
40 50 60 70 80 90 10 20 30 0.4 0.8 1.2
¯ hn2 2m t
Shamailov, Brand, arXiv:1805.07856
∆x2(t) = σfs
2 + σ2 CoM(t),
σ2
CoM(t) = σ2
" 1 + ✓ ~t 2Mσ2 ◆2#
∆x2 =N −1
d
Z (x hxi)2 [n(x) n0] dx Nd = Z [n(x) n0] dx σ2
0 =
~2 4∆P 2
σ2
fs, M
Shamailov, Brand, arXiv:1805.07856
50 100 150 200 20 40 60
n2
0¯
h2 ∆p2
5 10 15 20 25 50 100 150
5 10 15 20 25 50 100 150
5 10 15 20 25 50 100 150
hn2 2m
50 100 150 2 4 6 8 10 12
hn2 2m
x103 x102 x104
Shamailov, Brand, arXiv:1805.07856
σ2
GP =
π2 3γ2n2
0N 2 d
Shamailov, Brand, arXiv:1805.07856
γ
10-2 10-1 100 101 102 103 104
σ/ξ
0.5 1 1.5 2 2.5 σ0,min/ξ σfs/ξ
Nd
σ2
fsc2N 2 d
5 10 15
P0 = π¯ hn0 P0 = 2.5¯ hn0 P0 = 2¯ hn0 P0 = 1.5¯ hn0 P0 = 1¯ hn0 π2/3
(b) (a)
hn0 P ¯ hn0
−7 −5 −3 −1
P ¯ hn0
hn0
π/2 π 3π/2 2π π/2 π 3π/2 2π 3π/2 2π π/2 π
Nd = ✓ 1 v2
s
c2 ◆−1 ✓∂Es ∂µ + vsP mc2 ◆
P = mvsNd + 1 2~n0∆φ
Shamailov, Brand, arXiv:1805.07856
s (P) ≈ E∞ s (P) + Psvcf + 1
cf + N 2 d
−1 1 2 3 4 5
P ¯ hn0 2m ¯ h2n2
0(E − Eg)
π/2 π 3π/2 2π
γ = gm n0~2
as =1L, kc =4π L as =2L, kc =4π L as =1L, kc =8π L
0.0 0.2 0.4 x L 1.00 1.02 1.04 1.06 exp (u0 (x))
DODD
ODD-WALLS ALLS CENTRE ENTRE
for Photonic and Quantum Technologies