q-Tensor Squares of Polycyclic Groups Nora R. Rocco Universidade - - PowerPoint PPT Presentation

q tensor squares of polycyclic groups
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q-Tensor Squares of Polycyclic Groups Nora R. Rocco Universidade - - PowerPoint PPT Presentation

q-Tensor Squares of Polycyclic Groups Nora R. Rocco Universidade de Bras lia Institute of Exact Sciences Department of Mathematics (This is a joint work with E. Rodrigues and I. Dias, Brazil) Aug 11, 2017 N.R.Rocco - UnB, joint


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SLIDE 1

q-Tensor Squares of Polycyclic Groups

Nora´ ı R. Rocco

Universidade de Bras´ ılia Institute of Exact Sciences Department of Mathematics (This is a joint work with E. Rodrigues and I. Dias, Brazil)

Aug 11, 2017

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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The group ν(G)

Let G be any group and Gϕ an isomorphic copy of G, where g → gϕ, ∀g ∈ G. Define ν(G) := G, Gϕ | [g1, g2ϕ]g3 = [g1g3, (g2g3)ϕ] = [g1, g2ϕ]g3ϕ, for all g1, g2, g3 ∈ G. (N.R., 1991) Well known fact: Υ(G) := [G, Gϕ] ∼ = G ⊗ G, the non-abelian tensor square of G. G ⊗ G is a particular case of a more general non-abelian tensor product G ⊗ H of groups G, H acting on each other, as introduced by R. Brown and J.L. Loday in 1984.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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SLIDE 3

The group ν(G)

Let G be any group and Gϕ an isomorphic copy of G, where g → gϕ, ∀g ∈ G. Define ν(G) := G, Gϕ | [g1, g2ϕ]g3 = [g1g3, (g2g3)ϕ] = [g1, g2ϕ]g3ϕ, for all g1, g2, g3 ∈ G. (N.R., 1991) Well known fact: Υ(G) := [G, Gϕ] ∼ = G ⊗ G, the non-abelian tensor square of G. G ⊗ G is a particular case of a more general non-abelian tensor product G ⊗ H of groups G, H acting on each other, as introduced by R. Brown and J.L. Loday in 1984.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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SLIDE 4

The group ν(G)

Let G be any group and Gϕ an isomorphic copy of G, where g → gϕ, ∀g ∈ G. Define ν(G) := G, Gϕ | [g1, g2ϕ]g3 = [g1g3, (g2g3)ϕ] = [g1, g2ϕ]g3ϕ, for all g1, g2, g3 ∈ G. (N.R., 1991) Well known fact: Υ(G) := [G, Gϕ] ∼ = G ⊗ G, the non-abelian tensor square of G. G ⊗ G is a particular case of a more general non-abelian tensor product G ⊗ H of groups G, H acting on each other, as introduced by R. Brown and J.L. Loday in 1984.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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The group ν(G)

Let G be any group and Gϕ an isomorphic copy of G, where g → gϕ, ∀g ∈ G. Define ν(G) := G, Gϕ | [g1, g2ϕ]g3 = [g1g3, (g2g3)ϕ] = [g1, g2ϕ]g3ϕ, for all g1, g2, g3 ∈ G. (N.R., 1991) Well known fact: Υ(G) := [G, Gϕ] ∼ = G ⊗ G, the non-abelian tensor square of G. G ⊗ G is a particular case of a more general non-abelian tensor product G ⊗ H of groups G, H acting on each other, as introduced by R. Brown and J.L. Loday in 1984.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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The group ν(G)

Let G be any group and Gϕ an isomorphic copy of G, where g → gϕ, ∀g ∈ G. Define ν(G) := G, Gϕ | [g1, g2ϕ]g3 = [g1g3, (g2g3)ϕ] = [g1, g2ϕ]g3ϕ, for all g1, g2, g3 ∈ G. (N.R., 1991) Well known fact: Υ(G) := [G, Gϕ] ∼ = G ⊗ G, the non-abelian tensor square of G. G ⊗ G is a particular case of a more general non-abelian tensor product G ⊗ H of groups G, H acting on each other, as introduced by R. Brown and J.L. Loday in 1984.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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Extension to a modular version

D.Conduch´ e & C.Rodriguez-Fernandez (1992): non-abelian tensor product of q-crossed modules, q ≥ 0. Relations are abstractions of (qth−) powers and commutator relations in groups.

  • R. Brown (1990) explores its relationship with universal

q-central extensions of q-perfect groups. G.Ellis (1995) gives a construction related to the q-tensor product of normal subgroups of a larger group.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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Extension to a modular version

D.Conduch´ e & C.Rodriguez-Fernandez (1992): non-abelian tensor product of q-crossed modules, q ≥ 0. Relations are abstractions of (qth−) powers and commutator relations in groups.

  • R. Brown (1990) explores its relationship with universal

q-central extensions of q-perfect groups. G.Ellis (1995) gives a construction related to the q-tensor product of normal subgroups of a larger group.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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SLIDE 9

Extension to a modular version

D.Conduch´ e & C.Rodriguez-Fernandez (1992): non-abelian tensor product of q-crossed modules, q ≥ 0. Relations are abstractions of (qth−) powers and commutator relations in groups.

  • R. Brown (1990) explores its relationship with universal

q-central extensions of q-perfect groups. G.Ellis (1995) gives a construction related to the q-tensor product of normal subgroups of a larger group.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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Extension to a modular version

D.Conduch´ e & C.Rodriguez-Fernandez (1992): non-abelian tensor product of q-crossed modules, q ≥ 0. Relations are abstractions of (qth−) powers and commutator relations in groups.

  • R. Brown (1990) explores its relationship with universal

q-central extensions of q-perfect groups. G.Ellis (1995) gives a construction related to the q-tensor product of normal subgroups of a larger group.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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The Group νq(G)

  • T. Bueno (2006) introduces a variant of Ellis construction by

extending the commutator approach from ν(G) to a hat and commutator approach, νq(G), for all q ≥ 0. For q ≥ 1 let G = { k | k ∈ G} be a set of symbols and let F( G) be the free group over G (for q = 0 set G = ∅). In the free product ν(G) ∗ F( G), let J be the normal closure of the following elements, for all g, h, k, k1 ∈ G:

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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The Group νq(G)

  • T. Bueno (2006) introduces a variant of Ellis construction by

extending the commutator approach from ν(G) to a hat and commutator approach, νq(G), for all q ≥ 0. For q ≥ 1 let G = { k | k ∈ G} be a set of symbols and let F( G) be the free group over G (for q = 0 set G = ∅). In the free product ν(G) ∗ F( G), let J be the normal closure of the following elements, for all g, h, k, k1 ∈ G:

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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SLIDE 13

The Group νq(G)

  • T. Bueno (2006) introduces a variant of Ellis construction by

extending the commutator approach from ν(G) to a hat and commutator approach, νq(G), for all q ≥ 0. For q ≥ 1 let G = { k | k ∈ G} be a set of symbols and let F( G) be the free group over G (for q = 0 set G = ∅). In the free product ν(G) ∗ F( G), let J be the normal closure of the following elements, for all g, h, k, k1 ∈ G:

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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Defining Relations

g−1 k g ( kg)−1; (1) (hϕ)−1 k hϕ ( kh)−1; (2) ( k)−1[g, hϕ] k [gkq, (hkq)ϕ]−1; (3) ( k)−1 kk1 ( k1)−1(

q−1

  • i=1

[k, (k−i

1 )ϕ]kq−1−i)−1;

(4) [ k, k1] [kq, (kq

1 )ϕ]−1;

(5)

  • [g, h] [g, hϕ]−q.

(6)

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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νq(G) and some relevant sections

νq(G) := (ν(G) ∗ F( G))/J For q = 0 the set of all relations (1) to (6) is empty; in this case ν(G) ∗ F( G)/J ∼ = ν(G) G and Gϕ are embedded into νq(G), for all q ≥ 0 Set T = [G, Gϕ] ≤ νq(G) and let G be the subgroup of νq(G) generated by ( the images of) G The subgroup Υq(G) = TG is normal in νq(G) and νq(G) = Gϕ · (G · Υq(G))

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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νq(G) and some relevant sections

νq(G) := (ν(G) ∗ F( G))/J For q = 0 the set of all relations (1) to (6) is empty; in this case ν(G) ∗ F( G)/J ∼ = ν(G) G and Gϕ are embedded into νq(G), for all q ≥ 0 Set T = [G, Gϕ] ≤ νq(G) and let G be the subgroup of νq(G) generated by ( the images of) G The subgroup Υq(G) = TG is normal in νq(G) and νq(G) = Gϕ · (G · Υq(G))

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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SLIDE 17

νq(G) and some relevant sections

νq(G) := (ν(G) ∗ F( G))/J For q = 0 the set of all relations (1) to (6) is empty; in this case ν(G) ∗ F( G)/J ∼ = ν(G) G and Gϕ are embedded into νq(G), for all q ≥ 0 Set T = [G, Gϕ] ≤ νq(G) and let G be the subgroup of νq(G) generated by ( the images of) G The subgroup Υq(G) = TG is normal in νq(G) and νq(G) = Gϕ · (G · Υq(G))

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-18
SLIDE 18

νq(G) and some relevant sections

νq(G) := (ν(G) ∗ F( G))/J For q = 0 the set of all relations (1) to (6) is empty; in this case ν(G) ∗ F( G)/J ∼ = ν(G) G and Gϕ are embedded into νq(G), for all q ≥ 0 Set T = [G, Gϕ] ≤ νq(G) and let G be the subgroup of νq(G) generated by ( the images of) G The subgroup Υq(G) = TG is normal in νq(G) and νq(G) = Gϕ · (G · Υq(G))

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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SLIDE 19

νq(G) and some relevant sections

νq(G) := (ν(G) ∗ F( G))/J For q = 0 the set of all relations (1) to (6) is empty; in this case ν(G) ∗ F( G)/J ∼ = ν(G) G and Gϕ are embedded into νq(G), for all q ≥ 0 Set T = [G, Gϕ] ≤ νq(G) and let G be the subgroup of νq(G) generated by ( the images of) G The subgroup Υq(G) = TG is normal in νq(G) and νq(G) = Gϕ · (G · Υq(G))

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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νq(G) and G ⊗q G

(Ellis [1995], Bueno [2006]) Υq(G) ∼ = G ⊗q G, for all q ≥ 0. The q-exterior square G∧qG, is the quotient of G⊗qG by its subgroup k ⊗ k|k ∈ G. Thus, G∧qG ∼ = Υq(G)/∆q(G), where ∆q(G) = [g, gϕ] | g ∈ G. Let ρ′ : Υq(G) → G be induced by [g, hϕ] → [g, h], k → kq, for all g, h, k ∈ G. ⇒ Ker(ρ′)/∆q(G) ∼ = H2(G, Zq).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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νq(G) and G ⊗q G

(Ellis [1995], Bueno [2006]) Υq(G) ∼ = G ⊗q G, for all q ≥ 0. The q-exterior square G∧qG, is the quotient of G⊗qG by its subgroup k ⊗ k|k ∈ G. Thus, G∧qG ∼ = Υq(G)/∆q(G), where ∆q(G) = [g, gϕ] | g ∈ G. Let ρ′ : Υq(G) → G be induced by [g, hϕ] → [g, h], k → kq, for all g, h, k ∈ G. ⇒ Ker(ρ′)/∆q(G) ∼ = H2(G, Zq).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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νq(G) and G ⊗q G

(Ellis [1995], Bueno [2006]) Υq(G) ∼ = G ⊗q G, for all q ≥ 0. The q-exterior square G∧qG, is the quotient of G⊗qG by its subgroup k ⊗ k|k ∈ G. Thus, G∧qG ∼ = Υq(G)/∆q(G), where ∆q(G) = [g, gϕ] | g ∈ G. Let ρ′ : Υq(G) → G be induced by [g, hϕ] → [g, h], k → kq, for all g, h, k ∈ G. ⇒ Ker(ρ′)/∆q(G) ∼ = H2(G, Zq).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-23
SLIDE 23

νq(G) and G ⊗q G

(Ellis [1995], Bueno [2006]) Υq(G) ∼ = G ⊗q G, for all q ≥ 0. The q-exterior square G∧qG, is the quotient of G⊗qG by its subgroup k ⊗ k|k ∈ G. Thus, G∧qG ∼ = Υq(G)/∆q(G), where ∆q(G) = [g, gϕ] | g ∈ G. Let ρ′ : Υq(G) → G be induced by [g, hϕ] → [g, h], k → kq, for all g, h, k ∈ G. ⇒ Ker(ρ′)/∆q(G) ∼ = H2(G, Zq).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-24
SLIDE 24

νq(G) and G ⊗q G

(Ellis [1995], Bueno [2006]) Υq(G) ∼ = G ⊗q G, for all q ≥ 0. The q-exterior square G∧qG, is the quotient of G⊗qG by its subgroup k ⊗ k|k ∈ G. Thus, G∧qG ∼ = Υq(G)/∆q(G), where ∆q(G) = [g, gϕ] | g ∈ G. Let ρ′ : Υq(G) → G be induced by [g, hϕ] → [g, h], k → kq, for all g, h, k ∈ G. ⇒ Ker(ρ′)/∆q(G) ∼ = H2(G, Zq).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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Cyclic Groups

T.Bueno & N.R. [2011] Let d = gcd(q, n). Then C∞ ⊗q C∞ ∼ = C∞ × Cq, Cn ⊗q Cn ∼ =      Cn × Cd, if d is odd, Cn × Cd, if d is even and either 4|n or 4|q; C2n × Cd/2,

  • therwise.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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Cyclic Groups

T.Bueno & N.R. [2011] Let d = gcd(q, n). Then C∞ ⊗q C∞ ∼ = C∞ × Cq, Cn ⊗q Cn ∼ =      Cn × Cd, if d is odd, Cn × Cd, if d is even and either 4|n or 4|q; C2n × Cd/2,

  • therwise.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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Direct Products

T.Bueno & N.R. [2011] Let G = N × H, N = N/N′Nq and H = H/H′Hq. Then (i) νq(G) = N, Nϕ, N × [N, Hϕ][H, Nϕ] × H, Hϕ, H; (ii) H, Hϕ, H ∼ = νq(H); N, Nϕ, N ∼ = νq(N). (iii) Υq(G) = Υq(N) × [N, Hϕ][H, Nϕ] × Υq(H); (iv) [N, Hϕ] ∼ = N ⊗Zq H ∼ = [H, Nϕ]. (v) ∆q(N × H) = ∆q(N) × ∆(H) × U, where U = [x, yϕ][y, xϕ] | x ∈ N, y ∈ H.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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Direct Products

T.Bueno & N.R. [2011] Let G = N × H, N = N/N′Nq and H = H/H′Hq. Then (i) νq(G) = N, Nϕ, N × [N, Hϕ][H, Nϕ] × H, Hϕ, H; (ii) H, Hϕ, H ∼ = νq(H); N, Nϕ, N ∼ = νq(N). (iii) Υq(G) = Υq(N) × [N, Hϕ][H, Nϕ] × Υq(H); (iv) [N, Hϕ] ∼ = N ⊗Zq H ∼ = [H, Nϕ]. (v) ∆q(N × H) = ∆q(N) × ∆(H) × U, where U = [x, yϕ][y, xϕ] | x ∈ N, y ∈ H.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-29
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Direct Products

T.Bueno & N.R. [2011] Let G = N × H, N = N/N′Nq and H = H/H′Hq. Then (i) νq(G) = N, Nϕ, N × [N, Hϕ][H, Nϕ] × H, Hϕ, H; (ii) H, Hϕ, H ∼ = νq(H); N, Nϕ, N ∼ = νq(N). (iii) Υq(G) = Υq(N) × [N, Hϕ][H, Nϕ] × Υq(H); (iv) [N, Hϕ] ∼ = N ⊗Zq H ∼ = [H, Nϕ]. (v) ∆q(N × H) = ∆q(N) × ∆(H) × U, where U = [x, yϕ][y, xϕ] | x ∈ N, y ∈ H.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-30
SLIDE 30

Direct Products

T.Bueno & N.R. [2011] Let G = N × H, N = N/N′Nq and H = H/H′Hq. Then (i) νq(G) = N, Nϕ, N × [N, Hϕ][H, Nϕ] × H, Hϕ, H; (ii) H, Hϕ, H ∼ = νq(H); N, Nϕ, N ∼ = νq(N). (iii) Υq(G) = Υq(N) × [N, Hϕ][H, Nϕ] × Υq(H); (iv) [N, Hϕ] ∼ = N ⊗Zq H ∼ = [H, Nϕ]. (v) ∆q(N × H) = ∆q(N) × ∆(H) × U, where U = [x, yϕ][y, xϕ] | x ∈ N, y ∈ H.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-31
SLIDE 31

Direct Products

T.Bueno & N.R. [2011] Let G = N × H, N = N/N′Nq and H = H/H′Hq. Then (i) νq(G) = N, Nϕ, N × [N, Hϕ][H, Nϕ] × H, Hϕ, H; (ii) H, Hϕ, H ∼ = νq(H); N, Nϕ, N ∼ = νq(N). (iii) Υq(G) = Υq(N) × [N, Hϕ][H, Nϕ] × Υq(H); (iv) [N, Hϕ] ∼ = N ⊗Zq H ∼ = [H, Nϕ]. (v) ∆q(N × H) = ∆q(N) × ∆(H) × U, where U = [x, yϕ][y, xϕ] | x ∈ N, y ∈ H.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-32
SLIDE 32

Direct Products

T.Bueno & N.R. [2011] Let G = N × H, N = N/N′Nq and H = H/H′Hq. Then (i) νq(G) = N, Nϕ, N × [N, Hϕ][H, Nϕ] × H, Hϕ, H; (ii) H, Hϕ, H ∼ = νq(H); N, Nϕ, N ∼ = νq(N). (iii) Υq(G) = Υq(N) × [N, Hϕ][H, Nϕ] × Υq(H); (iv) [N, Hϕ] ∼ = N ⊗Zq H ∼ = [H, Nϕ]. (v) ∆q(N × H) = ∆q(N) × ∆(H) × U, where U = [x, yϕ][y, xϕ] | x ∈ N, y ∈ H.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

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f.g. Abelian Groups

If A = r

i=1 Ci, where Ci = xi, then

Υq(A) =

r

  • i=1

Υq(Ci) ×

  • 1≤j<k≤r

[Cj, Cϕ

k ][Ck, Cϕ j ].

Here we have Υq(Ci) = [xi, xϕ

i ],

xi and [Cj, Cϕ

k ][Ck, Cϕ j ] = [xj, xϕ k ][xk, xϕ j ], [xj, xϕ k ] .

In addition, ∆q(A) = r

i=1[xi, xϕ i ] × j<k[xj, xϕ k ][xk, xϕ j ].

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-34
SLIDE 34

f.g. Abelian Groups

If A = r

i=1 Ci, where Ci = xi, then

Υq(A) =

r

  • i=1

Υq(Ci) ×

  • 1≤j<k≤r

[Cj, Cϕ

k ][Ck, Cϕ j ].

Here we have Υq(Ci) = [xi, xϕ

i ],

xi and [Cj, Cϕ

k ][Ck, Cϕ j ] = [xj, xϕ k ][xk, xϕ j ], [xj, xϕ k ] .

In addition, ∆q(A) = r

i=1[xi, xϕ i ] × j<k[xj, xϕ k ][xk, xϕ j ].

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-35
SLIDE 35

f.g. Abelian Groups

If A = r

i=1 Ci, where Ci = xi, then

Υq(A) =

r

  • i=1

Υq(Ci) ×

  • 1≤j<k≤r

[Cj, Cϕ

k ][Ck, Cϕ j ].

Here we have Υq(Ci) = [xi, xϕ

i ],

xi and [Cj, Cϕ

k ][Ck, Cϕ j ] = [xj, xϕ k ][xk, xϕ j ], [xj, xϕ k ] .

In addition, ∆q(A) = r

i=1[xi, xϕ i ] × j<k[xj, xϕ k ][xk, xϕ j ].

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-36
SLIDE 36

f.g. Abelian Groups

If A = r

i=1 Ci, where Ci = xi, then

Υq(A) =

r

  • i=1

Υq(Ci) ×

  • 1≤j<k≤r

[Cj, Cϕ

k ][Ck, Cϕ j ].

Here we have Υq(Ci) = [xi, xϕ

i ],

xi and [Cj, Cϕ

k ][Ck, Cϕ j ] = [xj, xϕ k ][xk, xϕ j ], [xj, xϕ k ] .

In addition, ∆q(A) = r

i=1[xi, xϕ i ] × j<k[xj, xϕ k ][xk, xϕ j ].

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-37
SLIDE 37

Write Eq

X(A) :=

xi, [xj, xϕ

k ] | 1 ≤ i ≤ r, 1 ≤ j < k ≤ r.

We get Υq(A) = ∆q(A)Eq

X(A).

For q = 0, we have ∆(A) ∩ EX(A) = 1, giving the direct decomposition: Υ(A) = ∆(A) × EX(A). If q > 0 the above decomposition is not in general valid. In fact, Υq(G) = TG and ∆q(G) ≤ T, for any group G; thus, such a decompositions will depend on the relationship between T and G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-38
SLIDE 38

Write Eq

X(A) :=

xi, [xj, xϕ

k ] | 1 ≤ i ≤ r, 1 ≤ j < k ≤ r.

We get Υq(A) = ∆q(A)Eq

X(A).

For q = 0, we have ∆(A) ∩ EX(A) = 1, giving the direct decomposition: Υ(A) = ∆(A) × EX(A). If q > 0 the above decomposition is not in general valid. In fact, Υq(G) = TG and ∆q(G) ≤ T, for any group G; thus, such a decompositions will depend on the relationship between T and G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-39
SLIDE 39

Write Eq

X(A) :=

xi, [xj, xϕ

k ] | 1 ≤ i ≤ r, 1 ≤ j < k ≤ r.

We get Υq(A) = ∆q(A)Eq

X(A).

For q = 0, we have ∆(A) ∩ EX(A) = 1, giving the direct decomposition: Υ(A) = ∆(A) × EX(A). If q > 0 the above decomposition is not in general valid. In fact, Υq(G) = TG and ∆q(G) ≤ T, for any group G; thus, such a decompositions will depend on the relationship between T and G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-40
SLIDE 40

Write Eq

X(A) :=

xi, [xj, xϕ

k ] | 1 ≤ i ≤ r, 1 ≤ j < k ≤ r.

We get Υq(A) = ∆q(A)Eq

X(A).

For q = 0, we have ∆(A) ∩ EX(A) = 1, giving the direct decomposition: Υ(A) = ∆(A) × EX(A). If q > 0 the above decomposition is not in general valid. In fact, Υq(G) = TG and ∆q(G) ≤ T, for any group G; thus, such a decompositions will depend on the relationship between T and G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-41
SLIDE 41

Write Eq

X(A) :=

xi, [xj, xϕ

k ] | 1 ≤ i ≤ r, 1 ≤ j < k ≤ r.

We get Υq(A) = ∆q(A)Eq

X(A).

For q = 0, we have ∆(A) ∩ EX(A) = 1, giving the direct decomposition: Υ(A) = ∆(A) × EX(A). If q > 0 the above decomposition is not in general valid. In fact, Υq(G) = TG and ∆q(G) ≤ T, for any group G; thus, such a decompositions will depend on the relationship between T and G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-42
SLIDE 42

Write Eq

X(A) :=

xi, [xj, xϕ

k ] | 1 ≤ i ≤ r, 1 ≤ j < k ≤ r.

We get Υq(A) = ∆q(A)Eq

X(A).

For q = 0, we have ∆(A) ∩ EX(A) = 1, giving the direct decomposition: Υ(A) = ∆(A) × EX(A). If q > 0 the above decomposition is not in general valid. In fact, Υq(G) = TG and ∆q(G) ≤ T, for any group G; thus, such a decompositions will depend on the relationship between T and G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-43
SLIDE 43

Remark on ∆q(G)

∆q(G) essentially depends on q and Gab = G/G′ ∆q(G) does not depend on the particular set of generators of G: [N.R., 1994] Let X = {xi}i∈I be a set of generators of grp G (assume I totally

  • rdered). Then ∆q(G) is generated by the set

∆X = {si := [xi, xϕ

i ], tjk := [xj, xϕ k ][xk, xϕ j ], | i, j, k ∈ I, j < k}.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-44
SLIDE 44

Remark on ∆q(G)

∆q(G) essentially depends on q and Gab = G/G′ ∆q(G) does not depend on the particular set of generators of G: [N.R., 1994] Let X = {xi}i∈I be a set of generators of grp G (assume I totally

  • rdered). Then ∆q(G) is generated by the set

∆X = {si := [xi, xϕ

i ], tjk := [xj, xϕ k ][xk, xϕ j ], | i, j, k ∈ I, j < k}.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-45
SLIDE 45

Remark on ∆q(G)

∆q(G) essentially depends on q and Gab = G/G′ ∆q(G) does not depend on the particular set of generators of G: [N.R., 1994] Let X = {xi}i∈I be a set of generators of grp G (assume I totally

  • rdered). Then ∆q(G) is generated by the set

∆X = {si := [xi, xϕ

i ], tjk := [xj, xϕ k ][xk, xϕ j ], | i, j, k ∈ I, j < k}.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-46
SLIDE 46

For q = 0, [Blyth, Fumagalli and Morigi, 2009] extending results

  • f [Brown, Johnson & Robertson, 1987] and of [N.R., 1991,

1994] established conditions on f.g. Gab in order to describe the structure of G ⊗ G as a direct product of ∆(G) and the exterior square G ∧ G: [BFM, 2009] Let G be a group s.t. Gab is f.g. If Gab has no element of order 2, or if G′ has a complement in G, the G ⊗ G ∼ = ∆(G) × (G ∧ G) We can extend above result in some way for q ≥ 1 and q odd If q = 2 then ∆2(G) ≤ T ≤ G; consequently, such a direct decomposition is not in general possible if q is even

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-47
SLIDE 47

For q = 0, [Blyth, Fumagalli and Morigi, 2009] extending results

  • f [Brown, Johnson & Robertson, 1987] and of [N.R., 1991,

1994] established conditions on f.g. Gab in order to describe the structure of G ⊗ G as a direct product of ∆(G) and the exterior square G ∧ G: [BFM, 2009] Let G be a group s.t. Gab is f.g. If Gab has no element of order 2, or if G′ has a complement in G, the G ⊗ G ∼ = ∆(G) × (G ∧ G) We can extend above result in some way for q ≥ 1 and q odd If q = 2 then ∆2(G) ≤ T ≤ G; consequently, such a direct decomposition is not in general possible if q is even

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-48
SLIDE 48

For q = 0, [Blyth, Fumagalli and Morigi, 2009] extending results

  • f [Brown, Johnson & Robertson, 1987] and of [N.R., 1991,

1994] established conditions on f.g. Gab in order to describe the structure of G ⊗ G as a direct product of ∆(G) and the exterior square G ∧ G: [BFM, 2009] Let G be a group s.t. Gab is f.g. If Gab has no element of order 2, or if G′ has a complement in G, the G ⊗ G ∼ = ∆(G) × (G ∧ G) We can extend above result in some way for q ≥ 1 and q odd If q = 2 then ∆2(G) ≤ T ≤ G; consequently, such a direct decomposition is not in general possible if q is even

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-49
SLIDE 49

For q = 0, [Blyth, Fumagalli and Morigi, 2009] extending results

  • f [Brown, Johnson & Robertson, 1987] and of [N.R., 1991,

1994] established conditions on f.g. Gab in order to describe the structure of G ⊗ G as a direct product of ∆(G) and the exterior square G ∧ G: [BFM, 2009] Let G be a group s.t. Gab is f.g. If Gab has no element of order 2, or if G′ has a complement in G, the G ⊗ G ∼ = ∆(G) × (G ∧ G) We can extend above result in some way for q ≥ 1 and q odd If q = 2 then ∆2(G) ≤ T ≤ G; consequently, such a direct decomposition is not in general possible if q is even

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-50
SLIDE 50

[R & R, 2016] Let q > 1 be an odd integer and A a finitely generated abelian group given by the presentation A = x1, . . . , xr | xni

i , [xj, xk], 1 ≤ i, j, k ≤ r, j < k,

where we assume that nl+1 = · · · = nr = 0 in case the free part

  • f A is generated by {xl+1, . . . , xr}, 0 ≤ l ≤ r − 1. Write

di = gcd(q, ni) and djk = gcd(q, nj, nk), 1 ≤ i, j, k ≤ r, j < k. Then (i) ∆q(A) ∼ = r

i=1 Cdi × 1≤j<k≤r Cdjk and

Eq

X(A) ∼

= A ×

1≤j<k≤r Cdjk;

(ii) Υq(A) = ∆q(A) × Eq

X(A).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-51
SLIDE 51

[R & R, 2016] Let q > 1 be an odd integer and A a finitely generated abelian group given by the presentation A = x1, . . . , xr | xni

i , [xj, xk], 1 ≤ i, j, k ≤ r, j < k,

where we assume that nl+1 = · · · = nr = 0 in case the free part

  • f A is generated by {xl+1, . . . , xr}, 0 ≤ l ≤ r − 1. Write

di = gcd(q, ni) and djk = gcd(q, nj, nk), 1 ≤ i, j, k ≤ r, j < k. Then (i) ∆q(A) ∼ = r

i=1 Cdi × 1≤j<k≤r Cdjk and

Eq

X(A) ∼

= A ×

1≤j<k≤r Cdjk;

(ii) Υq(A) = ∆q(A) × Eq

X(A).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-52
SLIDE 52

[R & R, 2016] Let q > 1 be an odd integer and A a finitely generated abelian group given by the presentation A = x1, . . . , xr | xni

i , [xj, xk], 1 ≤ i, j, k ≤ r, j < k,

where we assume that nl+1 = · · · = nr = 0 in case the free part

  • f A is generated by {xl+1, . . . , xr}, 0 ≤ l ≤ r − 1. Write

di = gcd(q, ni) and djk = gcd(q, nj, nk), 1 ≤ i, j, k ≤ r, j < k. Then (i) ∆q(A) ∼ = r

i=1 Cdi × 1≤j<k≤r Cdjk and

Eq

X(A) ∼

= A ×

1≤j<k≤r Cdjk;

(ii) Υq(A) = ∆q(A) × Eq

X(A).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-53
SLIDE 53

[R & R, 2016] Let q > 1 be an odd integer and A a finitely generated abelian group given by the presentation A = x1, . . . , xr | xni

i , [xj, xk], 1 ≤ i, j, k ≤ r, j < k,

where we assume that nl+1 = · · · = nr = 0 in case the free part

  • f A is generated by {xl+1, . . . , xr}, 0 ≤ l ≤ r − 1. Write

di = gcd(q, ni) and djk = gcd(q, nj, nk), 1 ≤ i, j, k ≤ r, j < k. Then (i) ∆q(A) ∼ = r

i=1 Cdi × 1≤j<k≤r Cdjk and

Eq

X(A) ∼

= A ×

1≤j<k≤r Cdjk;

(ii) Υq(A) = ∆q(A) × Eq

X(A).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-54
SLIDE 54

Gab finiteley generated

[Thm - R.& R. 2016] Let q > 1 be an odd integer and assume Gab is f.g. Then (i) ∆q(G) ∩ Eq(G) = 1; (ii) ∆q(G) ∼ = ∆q(Gab); (iii) Υq(G) ∼ = ∆q(Gab) × (G ∧q G); (iv) If Gab is free abelian of rank r, then ∆q(G) is a homocyclic abelian group of exponent q, of rank r+1

2

  • .

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-55
SLIDE 55

Gab finiteley generated

[Thm - R.& R. 2016] Let q > 1 be an odd integer and assume Gab is f.g. Then (i) ∆q(G) ∩ Eq(G) = 1; (ii) ∆q(G) ∼ = ∆q(Gab); (iii) Υq(G) ∼ = ∆q(Gab) × (G ∧q G); (iv) If Gab is free abelian of rank r, then ∆q(G) is a homocyclic abelian group of exponent q, of rank r+1

2

  • .

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-56
SLIDE 56

[G. Ellis, 1989] - Computing G ∧q G from a presentation of G Let q ≥ 0 and let F/R be a free presentation of G. Then G ∧q G ∼ = F ′F q/[R, F]Rq. [Corollary] Let Fn be the free group of rank n. Then (i) [RR, 2016] For q ≥ 1 and q odd, Fn ⊗q Fn ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q. (ii) [BJR, 1987] For q = 0, Fn ⊗ Fn ∼ = C(n+1

2 )

× (Fn)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-57
SLIDE 57

[G. Ellis, 1989] - Computing G ∧q G from a presentation of G Let q ≥ 0 and let F/R be a free presentation of G. Then G ∧q G ∼ = F ′F q/[R, F]Rq. [Corollary] Let Fn be the free group of rank n. Then (i) [RR, 2016] For q ≥ 1 and q odd, Fn ⊗q Fn ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q. (ii) [BJR, 1987] For q = 0, Fn ⊗ Fn ∼ = C(n+1

2 )

× (Fn)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-58
SLIDE 58

[G. Ellis, 1989] - Computing G ∧q G from a presentation of G Let q ≥ 0 and let F/R be a free presentation of G. Then G ∧q G ∼ = F ′F q/[R, F]Rq. [Corollary] Let Fn be the free group of rank n. Then (i) [RR, 2016] For q ≥ 1 and q odd, Fn ⊗q Fn ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q. (ii) [BJR, 1987] For q = 0, Fn ⊗ Fn ∼ = C(n+1

2 )

× (Fn)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-59
SLIDE 59

[G. Ellis, 1989] - Computing G ∧q G from a presentation of G Let q ≥ 0 and let F/R be a free presentation of G. Then G ∧q G ∼ = F ′F q/[R, F]Rq. [Corollary] Let Fn be the free group of rank n. Then (i) [RR, 2016] For q ≥ 1 and q odd, Fn ⊗q Fn ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q. (ii) [BJR, 1987] For q = 0, Fn ⊗ Fn ∼ = C(n+1

2 )

× (Fn)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-60
SLIDE 60

[G. Ellis, 1989] - Computing G ∧q G from a presentation of G Let q ≥ 0 and let F/R be a free presentation of G. Then G ∧q G ∼ = F ′F q/[R, F]Rq. [Corollary] Let Fn be the free group of rank n. Then (i) [RR, 2016] For q ≥ 1 and q odd, Fn ⊗q Fn ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q. (ii) [BJR, 1987] For q = 0, Fn ⊗ Fn ∼ = C(n+1

2 )

× (Fn)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-61
SLIDE 61

[G. Ellis, 1989] - Computing G ∧q G from a presentation of G Let q ≥ 0 and let F/R be a free presentation of G. Then G ∧q G ∼ = F ′F q/[R, F]Rq. [Corollary] Let Fn be the free group of rank n. Then (i) [RR, 2016] For q ≥ 1 and q odd, Fn ⊗q Fn ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q. (ii) [BJR, 1987] For q = 0, Fn ⊗ Fn ∼ = C(n+1

2 )

× (Fn)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-62
SLIDE 62

[Corollary] Let Nn,c = Fn/γc+1(Fn) be the free nilpotent group of class c ≥ 1 and rank n > 1. Then (i) [R & R, 2016] For q ≥ 1 and q odd Nn,c ⊗q Nn,c ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q γc+1(Fn)qγc+2(Fn). (ii) [BFM 2010, Corollary 1.7] For q = 0, Nn,c ⊗ Nn,c ∼ = C(n+1

2 )

× (Nn,c+1)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-63
SLIDE 63

[Corollary] Let Nn,c = Fn/γc+1(Fn) be the free nilpotent group of class c ≥ 1 and rank n > 1. Then (i) [R & R, 2016] For q ≥ 1 and q odd Nn,c ⊗q Nn,c ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q γc+1(Fn)qγc+2(Fn). (ii) [BFM 2010, Corollary 1.7] For q = 0, Nn,c ⊗ Nn,c ∼ = C(n+1

2 )

× (Nn,c+1)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-64
SLIDE 64

[Corollary] Let Nn,c = Fn/γc+1(Fn) be the free nilpotent group of class c ≥ 1 and rank n > 1. Then (i) [R & R, 2016] For q ≥ 1 and q odd Nn,c ⊗q Nn,c ∼ = C(n+1

2 )

q

× (Fn)′(Fn)q γc+1(Fn)qγc+2(Fn). (ii) [BFM 2010, Corollary 1.7] For q = 0, Nn,c ⊗ Nn,c ∼ = C(n+1

2 )

× (Nn,c+1)′.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-65
SLIDE 65

f.g. nilpotent groups of class 2

[Thm] Let Nn,2 be the free nilpotent group of rank n > 1 and class 2, Nn,2 = Fn/γ3(Fn). Then, (i) [M.Bacon, 1994] Nn,2 ⊗ Nn,2 is free abelian of rank

1 3n(n2 + 3n − 1).

More precisely, we have Nn,2 ⊗ Nn,2 ∼ = ∆(F ab

n ) × M(Nn,2) × N ′ n,2.

(ii) [R. R., 2016] For q > 1 and q odd, Nn,2 ⊗q Nn,2 ∼ = (Cq)(((n+1

2 ))+Mn(3)) × N ′

n,2N q n,2,

where Mn(3) = 1

3(n3 − n) is the q−rank of

γ3(Nn,2)/γ3(Nn,2)qγ4(Nn,2).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-66
SLIDE 66

f.g. nilpotent groups of class 2

[Thm] Let Nn,2 be the free nilpotent group of rank n > 1 and class 2, Nn,2 = Fn/γ3(Fn). Then, (i) [M.Bacon, 1994] Nn,2 ⊗ Nn,2 is free abelian of rank

1 3n(n2 + 3n − 1).

More precisely, we have Nn,2 ⊗ Nn,2 ∼ = ∆(F ab

n ) × M(Nn,2) × N ′ n,2.

(ii) [R. R., 2016] For q > 1 and q odd, Nn,2 ⊗q Nn,2 ∼ = (Cq)(((n+1

2 ))+Mn(3)) × N ′

n,2N q n,2,

where Mn(3) = 1

3(n3 − n) is the q−rank of

γ3(Nn,2)/γ3(Nn,2)qγ4(Nn,2).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-67
SLIDE 67

f.g. nilpotent groups of class 2

[Thm] Let Nn,2 be the free nilpotent group of rank n > 1 and class 2, Nn,2 = Fn/γ3(Fn). Then, (i) [M.Bacon, 1994] Nn,2 ⊗ Nn,2 is free abelian of rank

1 3n(n2 + 3n − 1).

More precisely, we have Nn,2 ⊗ Nn,2 ∼ = ∆(F ab

n ) × M(Nn,2) × N ′ n,2.

(ii) [R. R., 2016] For q > 1 and q odd, Nn,2 ⊗q Nn,2 ∼ = (Cq)(((n+1

2 ))+Mn(3)) × N ′

n,2N q n,2,

where Mn(3) = 1

3(n3 − n) is the q−rank of

γ3(Nn,2)/γ3(Nn,2)qγ4(Nn,2).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-68
SLIDE 68

f.g. nilpotent groups of class 2

[Thm] Let Nn,2 be the free nilpotent group of rank n > 1 and class 2, Nn,2 = Fn/γ3(Fn). Then, (i) [M.Bacon, 1994] Nn,2 ⊗ Nn,2 is free abelian of rank

1 3n(n2 + 3n − 1).

More precisely, we have Nn,2 ⊗ Nn,2 ∼ = ∆(F ab

n ) × M(Nn,2) × N ′ n,2.

(ii) [R. R., 2016] For q > 1 and q odd, Nn,2 ⊗q Nn,2 ∼ = (Cq)(((n+1

2 ))+Mn(3)) × N ′

n,2N q n,2,

where Mn(3) = 1

3(n3 − n) is the q−rank of

γ3(Nn,2)/γ3(Nn,2)qγ4(Nn,2).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-69
SLIDE 69

f.g. nilpotent groups of class 2

[Thm] Let Nn,2 be the free nilpotent group of rank n > 1 and class 2, Nn,2 = Fn/γ3(Fn). Then, (i) [M.Bacon, 1994] Nn,2 ⊗ Nn,2 is free abelian of rank

1 3n(n2 + 3n − 1).

More precisely, we have Nn,2 ⊗ Nn,2 ∼ = ∆(F ab

n ) × M(Nn,2) × N ′ n,2.

(ii) [R. R., 2016] For q > 1 and q odd, Nn,2 ⊗q Nn,2 ∼ = (Cq)(((n+1

2 ))+Mn(3)) × N ′

n,2N q n,2,

where Mn(3) = 1

3(n3 − n) is the q−rank of

γ3(Nn,2)/γ3(Nn,2)qγ4(Nn,2).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-70
SLIDE 70

f.g. nilpotent groups of class 2

[Thm] Let Nn,2 be the free nilpotent group of rank n > 1 and class 2, Nn,2 = Fn/γ3(Fn). Then, (i) [M.Bacon, 1994] Nn,2 ⊗ Nn,2 is free abelian of rank

1 3n(n2 + 3n − 1).

More precisely, we have Nn,2 ⊗ Nn,2 ∼ = ∆(F ab

n ) × M(Nn,2) × N ′ n,2.

(ii) [R. R., 2016] For q > 1 and q odd, Nn,2 ⊗q Nn,2 ∼ = (Cq)(((n+1

2 ))+Mn(3)) × N ′

n,2N q n,2,

where Mn(3) = 1

3(n3 − n) is the q−rank of

γ3(Nn,2)/γ3(Nn,2)qγ4(Nn,2).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-71
SLIDE 71

f.g. nilpotent groups of class 2

[Thm] Let Nn,2 be the free nilpotent group of rank n > 1 and class 2, Nn,2 = Fn/γ3(Fn). Then, (i) [M.Bacon, 1994] Nn,2 ⊗ Nn,2 is free abelian of rank

1 3n(n2 + 3n − 1).

More precisely, we have Nn,2 ⊗ Nn,2 ∼ = ∆(F ab

n ) × M(Nn,2) × N ′ n,2.

(ii) [R. R., 2016] For q > 1 and q odd, Nn,2 ⊗q Nn,2 ∼ = (Cq)(((n+1

2 ))+Mn(3)) × N ′

n,2N q n,2,

where Mn(3) = 1

3(n3 − n) is the q−rank of

γ3(Nn,2)/γ3(Nn,2)qγ4(Nn,2).

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-72
SLIDE 72

Consequently, for q > 1 and q odd, d(Nn,2 ⊗q Nn,2) = 1 3(n3 + 3n2 + 2n). This is the least upper bound for d(G ⊗q G), G a class 2 nilpotent group with d(G) = n: [E.Rodrigues, 2011] Let G be a nilpotent group of class 2 with d(G) = n. Then G ⊗q G can be generated by at most 1

3n(n2 + 3n + 2) elements.

In particular, if G is finite and gcd(q, |G|) = 1 then d(G ⊗q G) ≤ n2.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-73
SLIDE 73

Consequently, for q > 1 and q odd, d(Nn,2 ⊗q Nn,2) = 1 3(n3 + 3n2 + 2n). This is the least upper bound for d(G ⊗q G), G a class 2 nilpotent group with d(G) = n: [E.Rodrigues, 2011] Let G be a nilpotent group of class 2 with d(G) = n. Then G ⊗q G can be generated by at most 1

3n(n2 + 3n + 2) elements.

In particular, if G is finite and gcd(q, |G|) = 1 then d(G ⊗q G) ≤ n2.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-74
SLIDE 74

Consequently, for q > 1 and q odd, d(Nn,2 ⊗q Nn,2) = 1 3(n3 + 3n2 + 2n). This is the least upper bound for d(G ⊗q G), G a class 2 nilpotent group with d(G) = n: [E.Rodrigues, 2011] Let G be a nilpotent group of class 2 with d(G) = n. Then G ⊗q G can be generated by at most 1

3n(n2 + 3n + 2) elements.

In particular, if G is finite and gcd(q, |G|) = 1 then d(G ⊗q G) ≤ n2.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-75
SLIDE 75

Consequently, for q > 1 and q odd, d(Nn,2 ⊗q Nn,2) = 1 3(n3 + 3n2 + 2n). This is the least upper bound for d(G ⊗q G), G a class 2 nilpotent group with d(G) = n: [E.Rodrigues, 2011] Let G be a nilpotent group of class 2 with d(G) = n. Then G ⊗q G can be generated by at most 1

3n(n2 + 3n + 2) elements.

In particular, if G is finite and gcd(q, |G|) = 1 then d(G ⊗q G) ≤ n2.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-76
SLIDE 76

Consequently, for q > 1 and q odd, d(Nn,2 ⊗q Nn,2) = 1 3(n3 + 3n2 + 2n). This is the least upper bound for d(G ⊗q G), G a class 2 nilpotent group with d(G) = n: [E.Rodrigues, 2011] Let G be a nilpotent group of class 2 with d(G) = n. Then G ⊗q G can be generated by at most 1

3n(n2 + 3n + 2) elements.

In particular, if G is finite and gcd(q, |G|) = 1 then d(G ⊗q G) ≤ n2.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-77
SLIDE 77

An example: The Heisenberg group in detail

Let H = F2/γ3(F2) be the Heisenberg group, where F2 denotes the free group of rank 2. By previous thm, part (ii) we have, for q > 1, q odd: H ⊗q H ∼ = (Cq)5 × H′Hq Now, H has the polycyclic presentation H = x, y, z | [y, x] = z, [z, x] = 1 = [z, y]. (7) and thus Υq(H) is generated by {[x, xϕ], [x, yϕ], [y, xϕ], [y, yϕ], [x, zϕ], [y, zϕ], ˆ x, ˆ y}.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-78
SLIDE 78

An example: The Heisenberg group in detail

Let H = F2/γ3(F2) be the Heisenberg group, where F2 denotes the free group of rank 2. By previous thm, part (ii) we have, for q > 1, q odd: H ⊗q H ∼ = (Cq)5 × H′Hq Now, H has the polycyclic presentation H = x, y, z | [y, x] = z, [z, x] = 1 = [z, y]. (7) and thus Υq(H) is generated by {[x, xϕ], [x, yϕ], [y, xϕ], [y, yϕ], [x, zϕ], [y, zϕ], ˆ x, ˆ y}.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-79
SLIDE 79

An example: The Heisenberg group in detail

Let H = F2/γ3(F2) be the Heisenberg group, where F2 denotes the free group of rank 2. By previous thm, part (ii) we have, for q > 1, q odd: H ⊗q H ∼ = (Cq)5 × H′Hq Now, H has the polycyclic presentation H = x, y, z | [y, x] = z, [z, x] = 1 = [z, y]. (7) and thus Υq(H) is generated by {[x, xϕ], [x, yϕ], [y, xϕ], [y, yϕ], [x, zϕ], [y, zϕ], ˆ x, ˆ y}.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-80
SLIDE 80

An example: The Heisenberg group in detail

Let H = F2/γ3(F2) be the Heisenberg group, where F2 denotes the free group of rank 2. By previous thm, part (ii) we have, for q > 1, q odd: H ⊗q H ∼ = (Cq)5 × H′Hq Now, H has the polycyclic presentation H = x, y, z | [y, x] = z, [z, x] = 1 = [z, y]. (7) and thus Υq(H) is generated by {[x, xϕ], [x, yϕ], [y, xϕ], [y, yϕ], [x, zϕ], [y, zϕ], ˆ x, ˆ y}.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-81
SLIDE 81

The Heisenberg grp, cont.

In addition, the following relations hold in νq(H): [x, xϕ]q = [x, zϕ]q = [y, zϕ]q = [y, yϕ]q = 1 ([x, yϕ][y, xϕ])q = 1 [x, yϕ]q = z−1 = ( z)−1 = [y, xϕ]−q [ y, x] = [y, xϕ]q2 (= zq), and all other generators commute. ∴ Υq(H) is a homomorphic image of the ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ], [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] | above relations.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-82
SLIDE 82

The Heisenberg grp, cont.

In addition, the following relations hold in νq(H): [x, xϕ]q = [x, zϕ]q = [y, zϕ]q = [y, yϕ]q = 1 ([x, yϕ][y, xϕ])q = 1 [x, yϕ]q = z−1 = ( z)−1 = [y, xϕ]−q [ y, x] = [y, xϕ]q2 (= zq), and all other generators commute. ∴ Υq(H) is a homomorphic image of the ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ], [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] | above relations.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-83
SLIDE 83

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-84
SLIDE 84

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-85
SLIDE 85

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-86
SLIDE 86

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-87
SLIDE 87

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-88
SLIDE 88

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-89
SLIDE 89

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-90
SLIDE 90

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-91
SLIDE 91

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-92
SLIDE 92

The Heisenberg grp, cont.

We have: H1 = ˆ x, ˆ y, [y, xϕ] ∼ = H′Hq = xq, yq, z ≤ H; By our previous results, if q = 0 or if q ≥ 1 and q is odd, then ∆q(H) = [x, yϕ][y, xϕ], [x, xϕ], [y, yϕ] ∼ = (Cq)3 ∼ = ∆q(Gab) H ∧q H ∼ = Eq(G) = ˆ x, ˆ y, [y, xϕ], [x, zϕ], [y, zϕ] ∼ = H1 × (Cq)2 Finally we have H ⊗q H ∼ = ∆q(Hab) × H ∧q H ∼ = H1 × (Cq)5, where H1 ∼ = a, b, c | [b, a] = cq2, [c, a] = 1 = [c, b] ∼ = H′Hq. In particular, for q = 0 we find H ⊗ H ∼ = (C∞)6, which is a result of R.Aboughazi, 1987.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-93
SLIDE 93

G polycyclic

Let G be polycyclic, given by a consistent polycyclic presentation, say G = F/R Our procedure is an adaptation to all q ≥ 0 of a method described by Eick and Nickel (2008) for the case q = 0 We can find a consistent polycyclic presentation for G∗ = F Rq[R, F] From this we get a consistent pcp for G ∧ G ∼ = (G∗)′(G∗)q

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-94
SLIDE 94

G polycyclic

Let G be polycyclic, given by a consistent polycyclic presentation, say G = F/R Our procedure is an adaptation to all q ≥ 0 of a method described by Eick and Nickel (2008) for the case q = 0 We can find a consistent polycyclic presentation for G∗ = F Rq[R, F] From this we get a consistent pcp for G ∧ G ∼ = (G∗)′(G∗)q

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-95
SLIDE 95

G polycyclic

Let G be polycyclic, given by a consistent polycyclic presentation, say G = F/R Our procedure is an adaptation to all q ≥ 0 of a method described by Eick and Nickel (2008) for the case q = 0 We can find a consistent polycyclic presentation for G∗ = F Rq[R, F] From this we get a consistent pcp for G ∧ G ∼ = (G∗)′(G∗)q

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-96
SLIDE 96

G polycyclic

Let G be polycyclic, given by a consistent polycyclic presentation, say G = F/R Our procedure is an adaptation to all q ≥ 0 of a method described by Eick and Nickel (2008) for the case q = 0 We can find a consistent polycyclic presentation for G∗ = F Rq[R, F] From this we get a consistent pcp for G ∧ G ∼ = (G∗)′(G∗)q

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-97
SLIDE 97

G polycyclic

Let G be polycyclic, given by a consistent polycyclic presentation, say G = F/R Our procedure is an adaptation to all q ≥ 0 of a method described by Eick and Nickel (2008) for the case q = 0 We can find a consistent polycyclic presentation for G∗ = F Rq[R, F] From this we get a consistent pcp for G ∧ G ∼ = (G∗)′(G∗)q

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-98
SLIDE 98

A pcp for τ q(G)

Let τ q(G) := νq(G)/∆q(G). We have τ q(G) ∼ = (G ∧q G) ⋊ (G × G). Can find a consistent pcp for τ q(G). Need the concept of a q−biderivation, which extends the concept of a crossed pairing (biderivation) to the context of q-tensor squares Crossed pairings have been used in order to determine homomorphic images of the non-abelian tensor square G ⊗ G. Let G and L be arbitrary groups.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-99
SLIDE 99

A pcp for τ q(G)

Let τ q(G) := νq(G)/∆q(G). We have τ q(G) ∼ = (G ∧q G) ⋊ (G × G). Can find a consistent pcp for τ q(G). Need the concept of a q−biderivation, which extends the concept of a crossed pairing (biderivation) to the context of q-tensor squares Crossed pairings have been used in order to determine homomorphic images of the non-abelian tensor square G ⊗ G. Let G and L be arbitrary groups.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-100
SLIDE 100

A pcp for τ q(G)

Let τ q(G) := νq(G)/∆q(G). We have τ q(G) ∼ = (G ∧q G) ⋊ (G × G). Can find a consistent pcp for τ q(G). Need the concept of a q−biderivation, which extends the concept of a crossed pairing (biderivation) to the context of q-tensor squares Crossed pairings have been used in order to determine homomorphic images of the non-abelian tensor square G ⊗ G. Let G and L be arbitrary groups.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-101
SLIDE 101

A pcp for τ q(G)

Let τ q(G) := νq(G)/∆q(G). We have τ q(G) ∼ = (G ∧q G) ⋊ (G × G). Can find a consistent pcp for τ q(G). Need the concept of a q−biderivation, which extends the concept of a crossed pairing (biderivation) to the context of q-tensor squares Crossed pairings have been used in order to determine homomorphic images of the non-abelian tensor square G ⊗ G. Let G and L be arbitrary groups.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-102
SLIDE 102

A pcp for τ q(G)

Let τ q(G) := νq(G)/∆q(G). We have τ q(G) ∼ = (G ∧q G) ⋊ (G × G). Can find a consistent pcp for τ q(G). Need the concept of a q−biderivation, which extends the concept of a crossed pairing (biderivation) to the context of q-tensor squares Crossed pairings have been used in order to determine homomorphic images of the non-abelian tensor square G ⊗ G. Let G and L be arbitrary groups.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-103
SLIDE 103

A pcp for τ q(G)

Let τ q(G) := νq(G)/∆q(G). We have τ q(G) ∼ = (G ∧q G) ⋊ (G × G). Can find a consistent pcp for τ q(G). Need the concept of a q−biderivation, which extends the concept of a crossed pairing (biderivation) to the context of q-tensor squares Crossed pairings have been used in order to determine homomorphic images of the non-abelian tensor square G ⊗ G. Let G and L be arbitrary groups.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-104
SLIDE 104

q−biderivations

  • Def. [I.Dias, 2011]

A function λ : G × G × G → L is called a q-biderivation if it satisfies the following properties, for all g, g1, h, h1, k1 ∈ G: (gg1, h, k)λ = (gg1, hg1, 1)λ (g1, h, k)λ (g, hh1, k)λ = (g, h1, 1)λ (gh1, hh1, k)λ ((1, 1, k)λ)−1 (g, h, 1)λ (1, 1, k)λ = (gkq, hkq, 1)λ (1, 1, kk1)λ = (1, 1, k)λ

q−1

  • i=1
  • (k, (k−i

1 )kq−1−i, 1)λ

  • (1, 1, k1)λ

[(1, 1, k)λ, (1, 1, k1)λ] = (kq, kq

1 , 1)λ

(1, 1, [g, h])λ = ((g, h, 1)λ)q .

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-105
SLIDE 105

q−biderivations

  • Def. [I.Dias, 2011]

A function λ : G × G × G → L is called a q-biderivation if it satisfies the following properties, for all g, g1, h, h1, k1 ∈ G: (gg1, h, k)λ = (gg1, hg1, 1)λ (g1, h, k)λ (g, hh1, k)λ = (g, h1, 1)λ (gh1, hh1, k)λ ((1, 1, k)λ)−1 (g, h, 1)λ (1, 1, k)λ = (gkq, hkq, 1)λ (1, 1, kk1)λ = (1, 1, k)λ

q−1

  • i=1
  • (k, (k−i

1 )kq−1−i, 1)λ

  • (1, 1, k1)λ

[(1, 1, k)λ, (1, 1, k1)λ] = (kq, kq

1 , 1)λ

(1, 1, [g, h])λ = ((g, h, 1)λ)q .

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-106
SLIDE 106

A consistent pcp for νq(G)

Can compute the image of the action of G and of the q−biderivation λ in the polycyclic presentation of G ∧q G ∼ = (G∗)′(G∗)q This will give a consistent pcp for τ q(G). Now νq(G) can be polycyclicly presented as a certain central extension of τ q(G). Finally, standard methods for polycyclic groups are used to find a consistent pcp for the q−tensor square G ⊗q G as a subgroup of νq(G): G ⊗q G ∼ = [G, Gϕ]G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-107
SLIDE 107

A consistent pcp for νq(G)

Can compute the image of the action of G and of the q−biderivation λ in the polycyclic presentation of G ∧q G ∼ = (G∗)′(G∗)q This will give a consistent pcp for τ q(G). Now νq(G) can be polycyclicly presented as a certain central extension of τ q(G). Finally, standard methods for polycyclic groups are used to find a consistent pcp for the q−tensor square G ⊗q G as a subgroup of νq(G): G ⊗q G ∼ = [G, Gϕ]G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-108
SLIDE 108

A consistent pcp for νq(G)

Can compute the image of the action of G and of the q−biderivation λ in the polycyclic presentation of G ∧q G ∼ = (G∗)′(G∗)q This will give a consistent pcp for τ q(G). Now νq(G) can be polycyclicly presented as a certain central extension of τ q(G). Finally, standard methods for polycyclic groups are used to find a consistent pcp for the q−tensor square G ⊗q G as a subgroup of νq(G): G ⊗q G ∼ = [G, Gϕ]G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-109
SLIDE 109

A consistent pcp for νq(G)

Can compute the image of the action of G and of the q−biderivation λ in the polycyclic presentation of G ∧q G ∼ = (G∗)′(G∗)q This will give a consistent pcp for τ q(G). Now νq(G) can be polycyclicly presented as a certain central extension of τ q(G). Finally, standard methods for polycyclic groups are used to find a consistent pcp for the q−tensor square G ⊗q G as a subgroup of νq(G): G ⊗q G ∼ = [G, Gϕ]G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-110
SLIDE 110

A consistent pcp for νq(G)

Can compute the image of the action of G and of the q−biderivation λ in the polycyclic presentation of G ∧q G ∼ = (G∗)′(G∗)q This will give a consistent pcp for τ q(G). Now νq(G) can be polycyclicly presented as a certain central extension of τ q(G). Finally, standard methods for polycyclic groups are used to find a consistent pcp for the q−tensor square G ⊗q G as a subgroup of νq(G): G ⊗q G ∼ = [G, Gϕ]G.

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017

slide-111
SLIDE 111

Thank You!

N.R.Rocco - UnB, joint with E.Rodrigues and I.Dias Groups St Andrews 2017 - Birmingham, UK - 05–13 Aug 2017