Outline Framework Antiderivative Functions Applications - - PowerPoint PPT Presentation

outline
SMART_READER_LITE
LIVE PREVIEW

Outline Framework Antiderivative Functions Applications - - PowerPoint PPT Presentation

Antiderivative Functions over F 2 n Valentin SUDER Seminar CALIN - Paris 13 April 12nd 2016. ComSec Lab, University of Waterloo ON, CANADA Outline Framework Antiderivative Functions Applications Conclusion Outline Framework Symmetric


slide-1
SLIDE 1

ComSec Lab, University of Waterloo ON, CANADA

Antiderivative Functions over F2n

Valentin SUDER

Seminar CALIN - Paris 13 April 12nd 2016.

slide-2
SLIDE 2

Outline

Framework Antiderivative Functions Applications Conclusion

slide-3
SLIDE 3

Outline

Framework Symmetric Cryptography Differential Attacks on Block Ciphers Polynomial Representation Problem Antiderivative Functions Applications Conclusion

slide-4
SLIDE 4

Framework Symmetric Cryptography

Design in Symmetric Cryptography

◮ Symmetric Cryptography: Alice and Bob share the same key.

1 / 30

slide-5
SLIDE 5

Framework Symmetric Cryptography

Design in Symmetric Cryptography

◮ Symmetric Cryptography: Alice and Bob share the same key. ◮ Primitives:

◮ Block ciphers; ◮ Stream ciphers; ◮ Hash functions; 1 / 30

slide-6
SLIDE 6

Framework Symmetric Cryptography

Design in Symmetric Cryptography

◮ Symmetric Cryptography: Alice and Bob share the same key. ◮ Primitives:

◮ Block ciphers; ◮ Stream ciphers; ◮ Hash functions;

Block Cipher E : Fm

2 × Fk 2

→ Fm

2

(M, K) → E(M, K) = C. For a fixed key K ∈ Fk

2,

EK(M) → C, is a permutation of Fm

2 .

1 / 30

slide-7
SLIDE 7

Framework Symmetric Cryptography

Design in Symmetric Cryptography

◮ Symmetric Cryptography: Alice and Bob share the same key. ◮ Primitives:

◮ Block ciphers; ◮ Stream ciphers; ◮ Hash functions;

Block Cipher E : Fm

2 × Fk 2

→ Fm

2

(M, K) → E(M, K) = C. For a fixed key K ∈ Fk

2,

EK(M) → C, is a permutation of Fm

2 . ◮ Rounds composed by smaller functions:

◮ Confusion (nonlinear); ◮ Diffusion (linear); 1 / 30

slide-8
SLIDE 8

Framework Symmetric Cryptography

Block Ciphers

Feistel Scheme and Substitution Permutation Network (SPN)

F Li Ri Li+1 Ri+1

RKi

b b b b b b

S S S

M C K

b b b

S S S

Add Round Key Add Round Key Permutation Permutation

Key expansion

2 / 30

slide-9
SLIDE 9

Framework Symmetric Cryptography

Design in Symmetric Cryptography

◮ Symmetric Cryptography: Alice and Bob share the same key. ◮ Primitives:

◮ Block ciphers; ◮ Stream ciphers; ◮ Hash functions;

◮ Rounds composed by smaller functions:

◮ Confusion (nonlinear); ◮ Diffusion (linear);

◮ Cryptographic requirements of the confusion part:

◮ Differential; ◮ Linear; ◮ Algebraic; ◮ . . . 3 / 30

slide-10
SLIDE 10

Framework Differential Attacks on Block Ciphers

Differential Properties of Sboxes

F : F2n → F2n

F F

α β

δF(α, β) = # {x | F(x) + F(x + α) = β} The greater the value δF(α, β), the more likely an attacker can find x ∈ F2n such that F(x) + F(x + α) = β.

4 / 30

slide-11
SLIDE 11

Framework Differential Attacks on Block Ciphers

Differential Cryptanalysis of the last round

b b b

P ′ C′ = C + ? K Key Expansion

RK0 RK1 RKR−1

F0 F1 FR−1

b b b

P C K Key Expansion

RK0 RK1 RKR−1

F0 F1 FR−1

RK′

FR−1 FR−1

β = ? Differential on R − 1 rounds (α → β) α

EK EK

5 / 30

slide-12
SLIDE 12

Framework Polynomial Representation

Polynomial representation of the functions F2n → F2n

F : F2n → F2n x → 2n−1

i=0

cix i, ci ∈ F2n.

Definition The algebraic degree of F is defined as deg(F) = max

0≤i≤2n−1{wt(i) | ci = 0}.

wt(i) is the binary Hamming weigth of the integer i.

◮ F(x) is said to be a permutation polynomial if the

associated function F is bijective.

◮ F is said to be 2-to-1 if the equation F(x) = c has exactly 0

  • r 2 solutions, for any c ∈ F2n.

6 / 30

slide-13
SLIDE 13

Framework Polynomial Representation

Discrete derivatives

F : F2n → F2n

Definition The discrete derivative of F in a direction α ∈ F∗

2n is defined as

∆αF(x) = F(x) + F(x + α). The differential uniformity of F is defined as δ(F) = max

α=0, β∈F2n #{x | ∆αF(x) = β}.

Definition [Lai94] The m-order derivative of F in directions α0, . . . , αm−1 ∈ F2n is: ∆α0,...,αm−1F(x) = ∆α0

  • ∆α1,...,αm−1F(x)
  • .

7 / 30

slide-14
SLIDE 14

Framework Polynomial Representation

Equivalences preserving differential uniformity (but not only . . . )

F, G : F2n → F2n

EA-equivalence F and G are Extended Affine (EA) equivalent if there are two affinea permutations A0, A1 : F2n → F2n and an affine function A2 : F2n → F2n such that F = A0 ◦ G ◦ A1 + A2.

aof algebraic degree 1.

CCZ-equivalence [Carlet-Charpin-Zinoviev98] F and G are CCZ-equivalent if their graphs {(x, F(x)) | x ∈ F2n} and {(x, G(x)) | x ∈ F2n} are affine equivalent, i.e. if there is an affine permutation L = (L0, L1) : F2n ×F2n → F2n ×F2n such that y = F(x) ⇔ L0(x, y) = G(L1(x, y)), ∀(x, y) ∈ F2

2n.

8 / 30

slide-15
SLIDE 15

Framework Polynomial Representation

Some properties

F : F2n → F2n

◮ α ∈ F∗ 2n is a c-linear structure of F, c ∈ F2n, if ∀x ∈ F2n

∆αF(x) = F(x) + F(x + α) = c.

◮ F is called APN (Almost Perfect Nonlinear) if

δ(F) = max

α=0, β∈F2n #{x | ∆αF(x) = β} = 2. ◮ EA and CCZ-equivalence preserve differential uniformity. ◮ EA-equivalence preserves algebraic degree. ◮ The discrete derivation makes the algebraic degree

decrease: deg(F)>deg(∆α0F)>deg(∆α0,α1F)> . . .

9 / 30

slide-16
SLIDE 16

Framework Polynomial Representation

Differences Distribution Table (DDT)

n = 4

10 / 30

α\β . 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 . 16 . . . . . . . . . . . . . . . 1 . . . 2 . 2 . 2 2 . 2 2 2 . 2 . 2 . . 2 . . 2 . 6 2 2 . . . . 2 . 3 . . 4 2 . . . 4 . . 2 . . 4 . . 4 . . . . . 2 2 2 2 2 4 . . . . 2 5 . 4 2 . 2 . 2 . 2 . . 2 2 . . . 6 . 2 . . 2 4 2 . . . . 2 . 2 . 2 7 2 2 . 2 . . 4 . . 2 . 2 . . . 2 8 . . . . . . . . 6 2 . . 4 . 4 . 9 . 2 2 . 2 . 2 . . 2 . 2 2 2 . . 10 2 2 . . 2 . 2 . . 2 2 2 . . . 2 11 . . . 2 . . . 2 2 . 2 . 2 . 4 2 12 . . . 2 2 2 . 2 2 2 2 . . . . 2 13 . 4 . 2 . . . . . . 2 4 . 4 . . 14 . . 2 2 2 . 2 2 . . 2 . . . 2 . 15 2 . 4 . 2 . 2 . . . . 2 2 . . 2

slide-17
SLIDE 17

Framework Problem

Problem Build new functions with desirable differential properties.

Classical Solutions

◮ Tweak known APN functions (e.g. switching method); ◮ Use correspondence with relative objects in:

Coding Theory, Combinatorics, Sequences Theory, . . .

◮ . . .

New Idea

◮ Build derivatives with prescribed images; ◮ Gather them as if they are derivatives of the same function; ◮ Retrieve the said function:

it should have the desired differential properties.

11 / 30

slide-18
SLIDE 18

Outline

Framework Antiderivative Functions Matrix point of view Properties Reconstruction Applications Conclusion

slide-19
SLIDE 19

Antiderivative Functions Matrix point of view

Derivative as a linear application over F2n

2n

F : F2n → F2n

∆αF(x) = F(x) + F(x + α) =

  • i

cixi +

  • i

ci(x + α)i . . . =

  • j

xj

i, i≻j

ciαi−j

12 / 30

slide-20
SLIDE 20

Antiderivative Functions Matrix point of view

Derivative as a linear application over F2n

2n

F : F2n → F2n

∆αF(x) = F(x) + F(x + α) =

  • i

cixi +

  • i

ci(x + α)i . . . =

  • j

xj

i, i≻j

ciαi−j (a(j)

0 , a(j) 1 , . . . , a(j) 2n−1)·(c0, c1, . . . , c2n−1)⊤,

a(j)

i

= αi−j if i ≻ j

  • therwise.

i ≻ j: supp(i) ⊃ supp(j)

12 / 30

slide-21
SLIDE 21

Antiderivative Functions Matrix point of view

Derivative as a linear application over F2n

2n

F : F2n → F2n

∆αF(x) = F(x) + F(x + α) =

  • i

cixi +

  • i

ci(x + α)i . . . =

  • j

xj

i, i≻j

ciαi−j (a(j)

0 , a(j) 1 , . . . , a(j) 2n−1)·(c0, c1, . . . , c2n−1)⊤,

a(j)

i

= αi−j if i ≻ j

  • therwise.

coeffs(∆αF) =   

a(0) ... a(0)

2n−1

...

a(2n−1) ... a(2n−1)

2n−1

  ·   

c0

. . .

c2n−1

   = M(α)   

c0

. . .

c2n−1

  

i ≻ j: supp(i) ⊃ supp(j)

12 / 30

slide-22
SLIDE 22

Antiderivative Functions Matrix point of view

Recursive Construction

n = 4

13 / 30

M(α)=

                             .

α α2 α3 α4 α5 α6 α7 α8 α9 α10 α11 α12 α13 α14 α15

. . .

α2

.

α4

.

α6

.

α8

.

α10

.

α12

.

α14

. . .

α

. .

α4 α5

. .

α8 α9

. .

α12 α13

. . . . . . .

α4

. . .

α8

. . .

α12

. . . . .

α α2 α3

. . . .

α8 α9 α10 α11

. . . . . . .

α2

. . . . .

α8

.

α10

. . . . . . .

α

. . . . . .

α8 α9

. . . . . . . . . . . . . . .

α8

. . . . . . . . .

α α2 α3 α4 α5 α6 α7

. . . . . . . . . . .

α2

.

α4

.

α6

. . . . . . . . . . .

α

. .

α4 α5

. . . . . . . . . . . . . . .

α4

. . . . . . . . . . . . .

α α2 α3

. . . . . . . . . . . . . . .

α2

. . . . . . . . . . . . . . .

α

. . . . . . . . . . . . . . . .                             

slide-23
SLIDE 23

Antiderivative Functions Matrix point of view

Correspondence

For α, γ ∈ F∗

2n and for any F : F2n → F2n: ◮ M(α) · M(γ) = M(γ) · M(α)

⇔ ∆α,γF(x) = ∆γ,αF(x)

◮ M(α) · M(γ) · M(α + γ) = 0

⇔ ∆α,γ,α+βF(x) = 0 in particular: M(α) · M(α) = M2(α) = 0 ⇔ ∆α,αF(x) = 0.

14 / 30

slide-24
SLIDE 24

Antiderivative Functions Properties

Derivative Functions

Theorem For all α ∈ F∗

2n, we have

Im(M(α)) = ker(M(α)). Dimension = 2n−1. Let f : F2n → F2n, then ∆αf (x) = 0 ⇔ ∃F : F2n → F2n such that ∆αF(x) = f (x).

  • H. Xiong, L. Qu, C. Li and Y. Li,

Some results on the differential functions over finite fields, AAECC 25(3): 189-195, 2014.

15 / 30

slide-25
SLIDE 25

Antiderivative Functions Properties

Example: generator matrix of ker(M(α))

n = 4

                             1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . α8 α9 α10 α11 α12 α13 α14 . . . α9 . α11 . α13 . . . α8 . . α11 α12 . . . . . . α11 . . . . . α8 α9 α10 . . . . . . . α9 . . . . . . . α8 . . . . . . . .                             

16 / 30

slide-26
SLIDE 26

Antiderivative Functions Properties

Example: generator matrix of ker(M(α))

n = 4 

                            1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . α8 α9 α10 α11 α12 α13 α14 . . . α9 . α11 . α13 . . . α8 . . α11 α12 . . . . . . α11 . . . . . α8 α9 α10 . . . . . . . α9 . . . . . . . α8 . . . . . . . .                              ·             a0 a1 a2 a3 a4 a5 a6 a7             =                              d0 d1 d2 d3 d4 d5 d6 d7 d8 d9 d10 d11 d12 d13 d14 d15                             

16 / 30

slide-27
SLIDE 27

Antiderivative Functions Properties

Example: generator matrix of ker(M(α))

n = 4

                             1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . . . . . . . . 1 . α8 α9 α10 α11 α12 α13 α14 . . . α9 . α11 . α13 . . . α8 . . α11 α12 . . . . . . α11 . . . . . α8 α9 α10 . . . . . . . α9 . . . . . . . α8 . . . . . . . .                              ·             a0 a1 a2 . a4 . . .             =                              d0 d1 d2 . d4 . . . d8 . . . . . . .                             

16 / 30

slide-28
SLIDE 28

Antiderivative Functions Properties

Higher-order Derivative Functions (I)

Let α0, . . . , αm−1 ∈ F∗

2n be F2-linearly independent

Theorem Im  

  • 0≤i≤m−1

M(αi)   =

  • 0≤i≤m−1

ker(M(αi)). Dimension = 2n−m.

17 / 30

slide-29
SLIDE 29

Antiderivative Functions Properties

Higher-order Derivative Functions (I)

Let α0, . . . , αm−1 ∈ F∗

2n be F2-linearly independent

Theorem Im  

  • 0≤i≤m−1

M(αi)   =

  • 0≤i≤m−1

ker(M(αi)). Dimension = 2n−m. Let f : F2n → F2n. There is a function F : F2n → F2n such that ∆α0,...,αm−1F(x) = f (x) if and only if ∆αif (x) = 0, 0 ≤ i ≤ m−1. (⇒ easy, ⇐ not easy)

17 / 30

slide-30
SLIDE 30

Antiderivative Functions Properties

Sketch of proof (I)

Im

  • 0≤i≤m−1 M(αi)
  • =

0≤i≤m−1 ker(M(αi))

By induction: We have Im (M(α0)M(α1)) = {M(α0)ν | ν ∈ Im(M(α1))} = Im(M(α0)|Im(M(α1))), and M(α0) commutes with M(α1), so Im(M(α0)|Im(M(α1))) = Im(M(α1)|Im(M(α0))) ⊂ Im(M(α1)). Thus, Im(M(α0)|Im(M(α1))) = ker(M(α0)|Im(M(α1))) = ker(M(α0)) ∩ Im(M(α1)) = ker(M(α0)) ∩ ker(M(α1)).

18 / 30

slide-31
SLIDE 31

Antiderivative Functions Properties

Sketch of proof (II)

Im

  • 0≤i≤m−1 M(αi)
  • =

0≤i≤m−1 ker(M(αi)) 19 / 30

Lemma dim(ker(H · G)) = dim(ker(H)) + dim(ker(H) ∩ Im(G)). By induction: dim

  • ker

m

  • i=1

M(αi)

  • =

m

  • k=1

dim k

  • i=1

ker(M(αi))

  • .

With the rank-nullity Theorem, we have: dim

  • ker

m

  • i=1

M(αi)

  • + dim
  • Im

m

  • i=1

M(αi)

  • = 2n
slide-32
SLIDE 32

Antiderivative Functions Properties

Sketch of proof (II)

Im

  • 0≤i≤m−1 M(αi)
  • =

0≤i≤m−1 ker(M(αi)) 19 / 30

Lemma dim(ker(H · G)) = dim(ker(H)) + dim(ker(H) ∩ Im(G)). By induction: dim

  • ker

m

  • i=1

M(αi)

  • =

m

  • k=1

dim k

  • i=1

ker(M(αi))

  • .

With the rank-nullity Theorem, we have:

m

  • k=1

dim k

  • i=1

ker(M(αi))

  • + dim

m

  • i=1

ker(M(αi))

  • = 2n
slide-33
SLIDE 33

Antiderivative Functions Properties

Sketch of proof (II)

Im

  • 0≤i≤m−1 M(αi)
  • =

0≤i≤m−1 ker(M(αi)) 19 / 30

Lemma dim(ker(H · G)) = dim(ker(H)) + dim(ker(H) ∩ Im(G)). By induction: dim

  • ker

m

  • i=1

M(αi)

  • =

m

  • k=1

dim k

  • i=1

ker(M(αi))

  • .

With the rank-nullity Theorem, we have:

m

  • k=1

dim k

  • i=1

ker(M(αi))

  • = 2n−2n−m ⇒ dim

m

  • i=1

ker(M(αi))

  • = 2n−m

(reminder: dim(ker(M(α))) = 2n−1)

slide-34
SLIDE 34

Antiderivative Functions Properties

Higher-order Derivative Functions (II)

Let α0, . . . , αm−1 ∈ F∗

2n be F2-linearly independent

Theorem ker  

  • 0≤i≤m−1

M(αi)   =

  • 0≤i≤m−1

ker(M(αi)). Dimension = 2n − 2n−m.

20 / 30

slide-35
SLIDE 35

Antiderivative Functions Properties

Higher-order Derivative Functions (II)

Let α0, . . . , αm−1 ∈ F∗

2n be F2-linearly independent

Theorem ker  

  • 0≤i≤m−1

M(αi)   =

  • 0≤i≤m−1

ker(M(αi)). Dimension = 2n − 2n−m. Let F : F2n → F2n. Then, ∆α0,...,αm−1F(x) = 0 if and only if F(x) = F0(x)+· · ·+Fm−1(x), where ∆αiFi(x) = 0, 0 ≤ i ≤ m − 1. (⇐ easy, ⇒ not easy)

20 / 30

slide-36
SLIDE 36

Antiderivative Functions Properties

Sketch of proof (I)

ker

  • 0≤i≤m−1 M(αi)
  • =

0≤i≤m−1 ker(M(αi))

We have ker  

  • 0≤i≤m−1

M(αi)   ⊇

  • 0≤i≤m−1

ker(M(αi)) and dim

  • ker

m

  • i=1

M(αi)

  • = 2n − 2n−m.

Also, for any β ∈ F2n F2-linearly independent from the αi’s, M(β)  

1≤i≤m

M(αi)   =

  • 1≤i≤m

(M(αi)M(β)) ⇓ ker(M(β)) ∩  

1≤i≤m

ker(M(αi))   =

  • 1≤i≤m

(ker(M(αi)) ∩ ker(M(β))) .

21 / 30

slide-37
SLIDE 37

Antiderivative Functions Properties

Sketch of proof (II)

Inclusion-Exclusion principle

Proposition[Inclusion-Exclusion] dim m

  • i=1

ker(M(αi))

  • =

m

  • k=1

(−1)k+1  

  • 1≤i1≤···≤ik≤m

dim (ker(M(αi1)) ∩ · · · ∩ ker(M(αik)))  

22 / 30

slide-38
SLIDE 38

Antiderivative Functions Properties

Sketch of proof (II)

Inclusion-Exclusion principle

Proposition[Inclusion-Exclusion] dim m

  • i=1

ker(M(αi))

  • =

m

  • k=1

(−1)k+1  

  • 1≤i1≤···≤ik≤m

dim (ker(M(αi1)) ∩ · · · ∩ ker(M(αik)))   Hence, dim  

1≤i≤m

ker(M(αi))   =

  • 1≤k≤m

(−1)k+1 m k

  • 2n−k

= 2n − 2n−m by induction on m.

22 / 30

slide-39
SLIDE 39

Antiderivative Functions Properties

Sketch of proof (II)

Inclusion-Exclusion principle

Proposition[Inclusion-Exclusion] dim m

  • i=1

ker(M(αi))

  • =

m

  • k=1

(−1)k+1  

  • 1≤i1≤···≤ik≤m

dim (ker(M(αi1)) ∩ · · · ∩ ker(M(αik)))   Hence, dim  

1≤i≤m

ker(M(αi))   =

  • 1≤k≤m

(−1)k+1 m k

  • 2n−k

= 2n − 2n−m by induction on m. Thus ker

  • 0≤i≤m−1 M(αi)

0≤i≤m−1 ker(M(αi))

22 / 30

slide-40
SLIDE 40

Antiderivative Functions Properties

Sketch of proof (II)

Inclusion-Exclusion principle

Proposition[Inclusion-Exclusion] dim m

  • i=1

ker(M(αi))

  • =

m

  • k=1

(−1)k+1  

  • 1≤i1≤···≤ik≤m

dim (ker(M(αi1)) ∩ · · · ∩ ker(M(αik)))   Hence, dim  

1≤i≤m

ker(M(αi))   =

  • 1≤k≤m

(−1)k+1 m k

  • 2n−k

= 2n − 2n−m by induction on m. Thus ker

  • 0≤i≤m−1 M(αi)
  • =

0≤i≤m−1 ker(M(αi))

22 / 30

slide-41
SLIDE 41

Antiderivative Functions Reconstruction

Antiderivatives

Theorem Let α0, . . . , αm−1 ∈ F∗

2n be F2-linearly independent.

Let fi : F2n → F2n be such that ∆αifi(x) = 0, 0 ≤ i ≤ m−1. Then, ∃F : F2n → F2n such that ∆αiF(x) = fi(x) if and only if ∆αifj(x) = ∆αjfi(x), for all 0 ≤ i, j ≤ m − 1. Due to the structure of the M(αi)’s, it is possible to build efficiently F : F2n → F2n from a compatible set of functions fi.

23 / 30

slide-42
SLIDE 42

Antiderivative Functions Reconstruction

Algorithm

Antiderivative: {(fi, αi) | 0 ≤ i ≤ m − 1} verifying conditions of consistency

  • 1. G ← generating matrix of

ker(M(α0));

  • 2. sol ← 0F2n

2n;

  • 3. F0 ← a solution of

M(α0) · F0 = f0;

  • 4. for i from 1 to m − 1 do:

5. Fi ← a solution of M(αi) · Fi = fi; 6. κ ← generating matrix of ker(M(αi)G); 7. tmp ← a solution of M(αi)G · tmp = M(αi) · (F0 + Fi + sol); 8. sol ← tmp; 9. G ← G · κ;

  • 10. return sol + F0

24 / 30

slide-43
SLIDE 43

Antiderivative Functions Reconstruction

A new equivalence

F, G : F2n → F2n

Definition F ∼V G F and G are said differentially equivalent w.r.t. a subspace V ⊆ F2n if ∆vF(x) = ∆vG(x), for all v ∈ V . Proposition F ∼V G ⇔ coeffs(F + G) ∈

  • v∈V

ker (M(v)) Furthermore, n − dim(V ) ≥ deg(F + G). Differential equivalence is different from CCZ-equivalence!

25 / 30

slide-44
SLIDE 44

Outline

Framework Antiderivative Functions Applications Differential Coset Quadratic APN functions Conclusion

slide-45
SLIDE 45

Applications Differential Coset

Example

z ∈ F16, z4 = z + 1

26 / 30

α\β . 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 . 16 . . . . . . . . . . . . . . . 1 . . . 2 . 2 . 2 2 . 2 2 2 . 2 . 2 . . 2 . . 2 . 6 2 2 . . . . 2 . 3 . . 4 2 . . . 4 . . 2 . . 4 . . 4 . . . . . 2 2 2 2 2 4 . . . . 2 5 . 4 2 . 2 . 2 . 2 . . 2 2 . . . 6 . 2 . . 2 4 2 . . . . 2 . 2 . 2 7 2 2 . 2 . . 4 . . 2 . 2 . . . 2 8 . . . . . . . . 6 2 . . 4 . 4 . 9 . 2 2 . 2 . 2 . . 2 . 2 2 2 . . 10 2 2 . . 2 . 2 . . 2 2 2 . . . 2 11 . . . 2 . . . 2 2 . 2 . 2 . 4 2 12 . . . 2 2 2 . 2 2 2 2 . . . . 2 13 . 4 . 2 . . . . . . 2 4 . 4 . . 14 . . 2 2 2 . 2 2 . . 2 . . . 2 . 15 2 . 4 . 2 . 2 . . . . 2 2 . . 2

slide-46
SLIDE 46

Applications Differential Coset

Example

z ∈ F16, z4 = z + 1

26 / 30

α\β . 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 . 16 . . . . . . . . . . . . . . . 1 . . . 2 . 2 . 2 2 . 2 2 2 . 2 . 2 . . 2 . . 2 . 6 2 2 . . . . 2 . 3 . . 4 2 . . . 4 . . 2 . . 4 . . 4 . . . . . 2 2 2 2 2 4 . . . . 2 5 . 4 2 . 2 . 2 . 2 . . 2 2 . . . 6 . 2 . . 2 4 2 . . . . 2 . 2 . 2 7 2 2 . 2 . . 4 . . 2 . 2 . . . 2 8 . . . . . . . . 6 2 . . 4 . 4 . 9 . 2 2 . 2 . 2 . . 2 . 2 2 2 . . 10 2 2 . . 2 . 2 . . 2 2 2 . . . 2 11 . . . 2 . . . 2 2 . 2 . 2 . 4 2 12 . . . 2 2 2 . 2 2 2 2 . . . . 2 13 . 4 . 2 . . . . . . 2 4 . 4 . . 14 . . 2 2 2 . 2 2 . . 2 . . . 2 . 15 2 . 4 . 2 . 2 . . . . 2 2 . . 2

slide-47
SLIDE 47

Applications Differential Coset

Example

z ∈ F16, z4 = z + 1

26 / 30

α\β . 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 . 16 . . . . . . . . . . . . . . . 1 . . . 2 . 2 . 2 2 . 2 2 2 . 2 . 2 . . 2 . . 2 . 6 2 2 . . . . 2 . 3 . . 4 2 . . . 4 . . 2 . . 4 . . 4 . . . . . 2 2 2 2 2 4 . . . . 2 5 . 4 2 . 2 . 2 . 2 . . 2 2 . . . 6 . 2 . . 2 4 2 . . . . 2 . 2 . 2 7 2 2 . 2 . . 4 . . 2 . 2 . . . 2 8 . . . . . . . . 6 2 . . 4 . 4 . 9 . 2 2 . 2 . 2 . . 2 . 2 2 2 . . 10 2 2 . . 2 . 2 . . 2 2 2 . . . 2 11 . . . 2 . . . 2 2 . 2 . 2 . 4 2 12 . . . 2 2 2 . 2 2 2 2 . . . . 2 13 . 4 . 2 . . . . . . 2 4 . 4 . . 14 . . 2 2 2 . 2 2 . . 2 . . . 2 . 15 2 . 4 . 2 . 2 . . . . 2 2 . . 2

slide-48
SLIDE 48

Applications Differential Coset

Example

z ∈ F16, z4 = z + 1

26 / 30

α\β . 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 . 16 . . . . . . . . . . . . . . . 1 . . . 2 . 2 . 2 2 . 2 2 2 . 2 . 2 . . 2 . . 2 . 6 2 2 . . . . 2 . 3 . . 4 2 . . . 4 . . 2 . . 4 . . 4 . . . . . 2 2 2 2 2 4 . . . . 2 5 . 4 2 . 2 . 2 . 2 . . 2 2 . . . 6 . 2 . . 2 4 2 . . . . 2 . 2 . 2 7 2 2 . 2 . . 4 . . 2 . 2 . . . 2 8 . . . . . . . . 6 2 . . 4 . 4 . 9 . 2 2 . 2 . 2 . . 2 . 2 2 2 . . 10 2 2 . . 2 . 2 . . 2 2 2 . . . 2 11 . . . 2 . . . 2 2 . 2 . 2 . 4 2 12 . . . 2 2 2 . 2 2 2 2 . . . . 2 13 . 4 . 2 . . . . . . 2 4 . 4 . . 14 . . 2 2 2 . 2 2 . . 2 . . . 2 . 15 2 . 4 . 2 . 2 . . . . 2 2 . . 2

slide-49
SLIDE 49

Applications Differential Coset

Example

z ∈ F16, z4 = z + 1

F(x) = z12x15 + zx14 + z12x13 + z12x12 + z8x11 + z14x10 + x9 + x8 + z2x7 + z5x6 + z14x5 + z4x4 + z9x3 + z4x2 + x + z2 Let V =

  • 0, 1, z, z4

.

27 / 30

slide-50
SLIDE 50

Applications Differential Coset

Example

z ∈ F16, z4 = z + 1

F(x) = z12x15 + zx14 + z12x13 + z12x12 + z8x11 + z14x10 + x9 + x8 + z2x7 + z5x6 + z14x5 + z4x4 + z9x3 + z4x2 + x + z2 Let V =

  • 0, 1, z, z4

. We want G : F16 → F16 such that: F ∼V G and δ(G) < δ(F) = 6.

27 / 30

slide-51
SLIDE 51

Applications Differential Coset

Example

z ∈ F16, z4 = z + 1

F(x) = z12x15 + zx14 + z12x13 + z12x12 + z8x11 + z14x10 + x9 + x8 + z2x7 + z5x6 + z14x5 + z4x4 + z9x3 + z4x2 + x + z2 Let V =

  • 0, 1, z, z4

. We want G : F16 → F16 such that: F ∼V G and δ(G) < δ(F) = 6. We pick h : F16 → F16 with coeffs(h) ∈ ker(M(z2)) ∩ ker(M(z3)).

27 / 30

slide-52
SLIDE 52

Applications Differential Coset

Example

z ∈ F16, z4 = z + 1

F(x) = z12x15 + zx14 + z12x13 + z12x12 + z8x11 + z14x10 + x9 + x8 + z2x7 + z5x6 + z14x5 + z4x4 + z9x3 + z4x2 + x + z2 Let V =

  • 0, 1, z, z4

. We want G : F16 → F16 such that: F ∼V G and δ(G) < δ(F) = 6. We pick h : F16 → F16 with coeffs(h) ∈ ker(M(z2)) ∩ ker(M(z3)). For instance: coeffs(h) = (z10, z13, z7, z12, z3, z7, z2, 0, z11, z2, z7, 0, z12, 0, 0, 0) δ(F + h) = 4

27 / 30

slide-53
SLIDE 53

Applications Differential Coset

Example

F : F16 → F16

28 / 30

α\β . 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 . 16 . . . . . . . . . . . . . . . 1 . . . 2 . 2 . 2 2 . 2 2 2 . 2 . 2 . . 2 . . 2 . 6 2 2 . . . . 2 . 3 . . 4 2 . . . 4 . . 2 . . 4 . . 4 . . . . . 2 2 2 2 2 4 . . . . 2 5 . 4 2 . 2 . 2 . 2 . . 2 2 . . . 6 . 2 . . 2 4 2 . . . . 2 . 2 . 2 7 2 2 . 2 . . 4 . . 2 . 2 . . . 2 8 . . . . . . . . 6 2 . . 4 . 4 . 9 . 2 2 . 2 . 2 . . 2 . 2 2 2 . . 10 2 2 . . 2 . 2 . . 2 2 2 . . . 2 11 . . . 2 . . . 2 2 . 2 . 2 . 4 2 12 . . . 2 2 2 . 2 2 2 2 . . . . 2 13 . 4 . 2 . . . . . . 2 4 . 4 . . 14 . . 2 2 2 . 2 2 . . 2 . . . 2 . 15 2 . 4 . 2 . 2 . . . . 2 2 . . 2

slide-54
SLIDE 54

Applications Differential Coset

Example

F + h : F16 → F16

28 / 30

α\β . 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 . 16 . . . . . . . . . . . . . . . 1 . . . 2 . 2 . 2 2 . 2 2 2 . 2 . 2 . . . . 2 . . 2 2 2 2 4 2 . . . 3 . . . 2 2 . 2 2 2 . 2 2 2 . . . 4 . . . . . 2 2 2 2 2 4 . . . . 2 5 2 2 . . . 2 4 2 . . . . . . . 4 6 2 . . 2 . . 2 4 2 . . . 2 . . 2 7 2 . 2 2 . . . . . . . . 2 2 4 2 8 2 . 2 . . . 2 4 . 4 2 . . . . . 9 2 . 2 . . . 2 . . 2 2 2 . 2 2 . 10 2 4 2 . . . 2 . 2 . . . 2 2 . . 11 . 2 2 . 2 . . . 2 2 2 . 2 2 . . 12 . . . . 2 2 2 2 . 2 2 4 . . . . 13 2 . 2 2 2 . . 2 2 . . . 2 . . 2 14 2 . . 2 . . . 2 . 2 2 . 4 . . 2 15 2 . 4 . 2 . 2 . . . . 2 2 . . 2

slide-55
SLIDE 55

Applications Quadratic APN functions

Correspondence with previous works

Proposition A function is quadratic if and only if all its derivatives are affines.

  • 1. Choose 2-to-1 affine derivatives that are compatible
  • 2. Verify that the F2-linear combinations are again 2-to-1
  • 3. Apply the algorithm to find a quadratic APN function
  • G. Weng, Y. Tan and G. Gong,

On Quadratic Almost Perfect Nonlinear Functions and their Related Algebraic Object, WCC 2013.

  • Y. Yu, M. Wang and Y. Li,

A matrix approach for constructing quadratic APN functions, WCC 2013.

29 / 30

slide-56
SLIDE 56

Outline

Framework Antiderivative Functions Applications Conclusion

slide-57
SLIDE 57

Conclusion

Perspectives and open problems

◮ Characterize 2-to-1 functions/derivatives; ◮ Understand when the sum of two of them is again 2-to-1; ◮ How many APN functions in a same differential coset? ◮ Is it possible to preserve bijectivity? ◮ What are the possible shapes for DDT of APN functions? ◮ Extend to Fpn, with p an odd prime.

30 / 30