Optimal Investment with State-Dependent Constraints
Carole Bernard SAFI 2011, Ann Arbor, May 2011.
Carole Bernard Optimal Investment with State-Dependent Constraints 1/41
Optimal Investment with State-Dependent Constraints Carole Bernard - - PowerPoint PPT Presentation
Optimal Investment with State-Dependent Constraints Carole Bernard SAFI 2011, Ann Arbor, May 2011. Carole Bernard Optimal Investment with State-Dependent Constraints 1/41 Introduction Cost-Efficiency Examples State-Dependent Constraints
Carole Bernard Optimal Investment with State-Dependent Constraints 1/41
Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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2
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
{Y | Y ∼F} {E [ξTY ]} =
{Y | Y ∼F} c(Y )
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
{Y | Y ∼F} {E [ξTY ]} =
{Y | Y ∼F} c(Y )
Carole Bernard Optimal Investment with State-Dependent Constraints 5/41
Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
{Y | Y ∼F} {E [ξTY ]} =
{Y | Y ∼F} c(Y )
Carole Bernard Optimal Investment with State-Dependent Constraints 5/41
Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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4.
S2 = 64
1 4 1 16
X2 = 1 S1 = 32
p
p
1 2 6 16
X2 = 2 S1 = 8
p
1 4 9 16
X2 = 3 E[U(X2)] = U(1) + U(3) 4 + U(2) 2 , PD = Cheapest = 3 2 PX2 = Price of X2 = 1 16 + 6 162 + 9 163
Efficiency cost = PX2 − PD
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
2
4.
S2 = 64
1 4 1 16
Y2 = 3 S1 = 32
p
p
1 2 6 16
Y2 = 2 S1 = 8
p
1 4 9 16
Y2 = 1 E[U(Y2)] = U(3) + U(1) 4 + U(2) 2 , PD = Cheapest = 3 2 X2 and Y2 have the same distribution under the physical measure PX2 = Price of X2 = 1 16 + 6 162 + 9 163
Efficiency cost = PX2 − PD
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
2
4.
S2 = 64
1 4 1 16
X2 = 1 S1 = 32
q
q
1 2 6 16
X2 = 2 S1 = 8
q
1 4 9 16
X2 = 3 E[U(X2)] = U(1) + U(3) 4 + U(2) 2 , PD = Cheapest = 1 163 + 6 162 + 9 161
2 c(X2) = Price of X2 = 1 16 + 6 162 + 9 163
2 , Efficiency cost = PX2 − PD
Carole Bernard Optimal Investment with State-Dependent Constraints 10/41
Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
2
4.
S2 = 64
1 4 1 16
Y2 = 3 S1 = 32
q
q
1 2 6 16
Y2 = 2 S1 = 8
q
1 4 9 16
Y2 = 1 E[U(X2)] = U(1) + U(3) 4 + U(2) 2 , c(Y2) = 1 163 + 6 162 + 9 161
2 c(X2) = Price of X2 = 1 16 + 6 162 + 9 163
2 Efficiency cost = PX2 − PD
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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XT (EP[U(XT)]) where U is increasing.
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3
XT P(XT > K)
4
T
T
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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XT (EP[U(XT)]) where U is increasing.
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3
XT P(XT > K)
4
T
T
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T in the previous slide is cost-efficient.
Carole Bernard Optimal Investment with State-Dependent Constraints 13/41
Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T in the previous slide is cost-efficient.
Carole Bernard Optimal Investment with State-Dependent Constraints 13/41
Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T in the previous slide is cost-efficient.
Carole Bernard Optimal Investment with State-Dependent Constraints 13/41
Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
XT
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
{XT | XT ∼F} E[ξTXT]
T = F −1 (1 − Fξ (ξT)) .
T ∼ F and X⋆ T is a.s. unique such that
T) = E[ξTX⋆ T]
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
XT
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
Z (U), then
Z (U) F −1 X (1 − U)] E[F −1 Z (U) X] E[F −1 Z (U) F −1 X (U)]
X (1 − Fξ(ξT))] c(XT) E[ξTF −1 X (Fξ(ξT))]
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
{XT | XT ∼F} E[ξTXT]
T
T = F −1 (Fξ (ξT))
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T = F −1 (1 − Fξ (ξT))
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
t
θ σ (µ− σ2 2 )t−(r+ θ2 2 )t and b = µ−r
σ2 .
T = F −1 (FST (ST))
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
1 T
T
0 ln(St)dt − K
k=1 S kT
n
n − K
T = d
√ 3 T
1− 1
√ 3
2 −
3
2
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
40 60 80 100 120 140 160 180 200 220 240 260 20 40 60 80 100 120 Stock Price at maturity ST Payoff YT
*
ZT
*
With σ = 20%, µ = 9%, r = 5%, S0 = 100, T = 1 year, K = 100, n = 12. C(X⋆
T ) = 5.77 < Price(geometric Asian) = 5.94 < C(Z⋆ T ) = 9.03. Carole Bernard Optimal Investment with State-Dependent Constraints 23/41
Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T = F −1 L
0e2
2
+
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
100 200 300 400 500 20 40 60 80 100 ST Payoff cost efficient payoff that gives same payoff distrib as the put option Y* Best one Put option
With σ = 20%, µ = 9%, r = 5%, S0 = 100, T = 1 year, K = 100. Distributional price of the put = 3.14 Price of the put = 5.57 Efficiency loss for the put = 5.57-3.14= 2.43
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
1 Other sources of uncertainty: Stochastic interest rates or
2 Transaction costs, frictions 3 Intermediary consumption. 4 Often we are looking at an isolated contract: the theory
5 State-dependent needs
risk) by purchasing a put option,
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
{XT | XT ∼F} E [ξTXT] .
{YT | YT ∼F, S} E [ξTYT] .
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T given by
T = F −1(f (ξT, ξt))
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
u (p) = 1 − u for all 0 < p 1
T is given by
T = F −1 (1 − (FξT (ξT)))
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T exists and is unique. It
T = F −1 (G(FξT (ξT))) ,
u (1) and can be
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T = F −1 [G(F (ST))] ,
T := F −1 [(1 − F(ST))1ST <ℓ + (F(ST) − F(ℓ)) 1ST ℓ] .
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
50 100 150 50 100 150 200 250 ST YT
*
T as a function of ST. Parameters: ℓ = 100, S0 = 100, µ = 0.05,
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T = F −1
ln
St/T T
T ) ln(S0)
σ
T
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
T as a function of ST where ℓ = 100, S0 = 100,
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Introduction Cost-Efficiency Examples State-Dependent Constraints Conclusions
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◮ Tankov, P., 2011. “Improved Frechet bounds and model-free pricing of multi-asset options,” Journal of Applied Probability, forthcoming. ◮ Vanduffel, S., Chernih, A., Maj, M., Schoutens, W. 2009. “On the Suboptimality of Path-dependent Pay-offs in L´ evy markets”, Applied Mathematical Finance.