on truncated discrete moment problems
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On truncated discrete moment problems Tobias Kuna University of Reading, UK (Joint work with Maria Infusino, Joel Lebowitz, Eugene Speer) IWOTA 2019 Lisbon 26th July T. Kuna On truncated discrete moment problems Discrete truncated moment


  1. On truncated discrete moment problems Tobias Kuna University of Reading, UK (Joint work with Maria Infusino, Joel Lebowitz, Eugene Speer) IWOTA 2019 Lisbon – 26th July T. Kuna On truncated discrete moment problems

  2. Discrete truncated moment problem This talk focus on K discrete subset of R d for d = 1 ; n ∈ N or d ≥ 2 , n = 2 mainly K = N 0 or K = Z d . d − dimensional truncated K − moment problem of degree n � m ( 0 ) , . . . , m ( n ) � with m ( k ) a tuple Given m : = � � m ( k ) j 1 , ... , j d j r ∈ N 0 ; ∑ d r = 1 j r = k with m ( k ) j 1 , ... , j d ∈ R . Find a nonnegative Radon measure µ supported in K s.t. � m ( k ) K x j 1 1 . . . x j d ∀ k ; j r ∈ N 0 with ∑ j 1 , ... , j d = d µ ( dx ) , j r = n r W.l.o.g. we can assume m 0 = 1 and µ is a probability measure on K . We can use that the set is discrete m ( k ) j 1 , ... , j d = ∑ x j 1 1 . . . x j d d µ ( { x } ) , x ∈ K T. Kuna On truncated discrete moment problems

  3. Motivation for the discrete TMP Main motivation (for me) Moment problem for point processes Complex systems, Material science, Statistical mechanics Point processes Let R be a Riemannian manifold. � � δ r i ∈ D ′ ( R ) : I countable and r i ∈ R ∈ ⊂ D ′ ( R ) K : = ∑ i ∈ I A measure µ on K is called a point process. K is infinite dimensional d = ∞ . all element of K are Radon measures. Interpretation: µ is probability to find point configuration η . T. Kuna On truncated discrete moment problems

  4. Relation to N d 0 -TMP For η = ∑ i ∈ I δ r i ∈ K , define N A ( η ) : = η ( A ) = number of points in η which are in A By definition N A : K → N 0 . Finite dimensional distribution of µ One-dimensional distributions µ A : µ A ( C ) : = µ ( { η : N A ( η ) ∈ C } ) Push-forward of µ w.r.t. N A . Two-dimensional distribution µ A 1 , A 2 given by µ A 1 , A 2 ( C 1 × C 2 ) : = µ ( { η : N A i ( η ) ∈ C i } ) and so on Support of µ A is N 0 . Support of µ A 1 , A 2 is N 0 × N 0 . and so on T. Kuna On truncated discrete moment problems

  5. General convex analysis Generalized Tchakaloff Thm (Richter-Bayer-Teichmann) m has a N 0 − representing measure � criterion to solve { 0 , 1 , . . . , N } -TMP ∃ N ∈ N s.t. m has a { 0 , 1 , . . . , N }− representing measure criterion to solve N 0 -TMP depending on (unbeknown) N T. Kuna On truncated discrete moment problems

  6. Solving { 0 , 1 , . . . , N } -TMP Fix n , N ∈ N s.t. N ≥ n . Aim: Characterize the set S N of all n − tuple admitting m = ( m 1 , . . . , m n ) ∈ R n a { 0 , 1 , . . . , N } -representing probability measures. Every { 0 , 1 , . . . , N } -representing probability for m is a convex combination of probabilities concentrated at k = 0 , 1 , . . . , N . Hence S N is the convex hull of A N : = { ( k , k 2 , . . . , k n ) | k = 0 , 1 , . . . , N } Classical convex analysis yields, that S N is the intersection of finitely many closed half-spaces H containing A N whose � ∂ H contains at least n points � bounding hyperplanes ∂ H ↔ from A N   polynomials of degree n with leading coefficient ± 1   bounding hyperplanes ∂ H ↔   n distinct roots in { 0 , 1 , . . . , N }   nonnegative on { 0 , 1 , . . . , N } T. Kuna On truncated discrete moment problems

  7. Solving { 0 , 1 , . . . , N } -TMP   polynomials of degree n with leading coefficient + 1   P n , N : =   n distinct roots in { 0 , 1 , . . . , N }   nonnegative on { 0 , 1 , . . . , N } If n = 2 j even, any P ∈ P n , N is of the form: P ( x ) = � x − k 1 �� x − ( k 1 + 1 ) � � x − k j �� x − ( k j + 1 ) � . . . with zeros k 1 < k 1 + 1 < k 2 < k 2 + 1 < . . . < k j in { 0 , 1 , . . . , N } . If n = 2 j + 1 odd, any P ∈ P n , N is of the form: � x − k 1 �� x − ( k 1 + 1 ) � � x − k j �� x − ( k j + 1 ) � P ( x ) = x . . . with zeros 0 < k 1 < k 1 + 1 < k 2 < k 2 + 1 < . . . < k j in { 0 , 1 , . . . , N } .   polynomials of degree n with leading coefficient − 1   Q n , N : = = { P ( x )( N − x ) | P ∈ P n − 1 , N − 1 }   n distinct roots in { 0 , 1 , . . . , N }   nonnegative on { 0 , 1 , . . . , N } T. Kuna On truncated discrete moment problems

  8. From { 0 , 1 , . . . , N } -TMP to N 0 -TMP Generalized Tchakaloff Thm (Richter-Bayer-Teichmann) criterion to solve { 0 , 1 , . . . , N } -TMP m has a N 0 − representing probability m has a { 0 , 1 , . . . , N } -repr. prob. � ∃ N ∈ N s.t. m has a � { 0 , 1 , . . . , N }− representing probability L m ( p ) ≥ 0 , ∀ p ∈ P n , N ∪ Q n , N first criterion to solve N 0 -TMP m has a N 0 − representing probability � ∃ N ∈ N s.t. L m ( p ) ≥ 0 for all p ∈ P n , N ∪ Q n , N Problem: How to identify or get rid of N ? T. Kuna On truncated discrete moment problems

  9. N independent condition Note that P n , N ⊂ P n , N + 1 Define P n : = � N ∈ N P n , N . � ⇒ � � � m has a N 0 -representing measure L m ( p ) ≥ 0 ∀ p ∈ P n . Recall � m has a { 0 , 1 , . . . , N } -repr. prob. � ⇔ � � m has a N 0 -repr. prob. for some N large enough The condition L m (( M − x ) p ) ≥ 0 ML m ( p ) ≥ L m ( xp ) L m ( p ) ≥ 1 � � � L m ( p ) ≥ 0 ∀ p ∈ Q n , M ⇔ ML which implies that L m ( p ) ≥ 0 , ∀ p ∈ P n − 1 and if L m ( p ) = 0 for some p ∈ P n − 1 , then L m ( xp ) = 0 Necessary conditions L m ( p ) ≥ 0 , ∀ p ∈ P n ∪ P n − 1 m has a N 0 − repr.prob. ⇒ if L m ( p ) = 0 for some p ∈ P n − 1 then L m ( xp ) = 0 T. Kuna On truncated discrete moment problems

  10. Theorem (Infusino, K., Lebowitz, Speer, 2017) L m ( p ) ≥ 0 , ∀ p ∈ P n ∪ P n − 1 m has a N 0 − repr.prob. ⇔ if L m ( p ) = 0 for some p ∈ P n − 1 then L m ( xp ) = 0 Moreover, non of the conditions can be dropped. Proof of ⇐ : One need to derive an a priori bound on N using only the above conditions not realizability. Previous results: Karlin and Studden 1966 on K = N 0 ∪ { ∞ } . Solvability condition depending on an unknown parameter The best one could hope to obtain using Semi-algebraic techniques is conditions p 2 � ≥ 0 �� x − k �� x − ( k + 1 ) � ∀ p polynomial and ∀ k ∈ N 0 L m Challenge: Can one reduce the conditions further by making them m dependent? T. Kuna On truncated discrete moment problems

  11. m dependent conditions: what was known Case n = 1: � � � � m = ( m 1 ) is realizable ⇔ m 1 ≥ 0 Case n = 2: (Yamada 1961) � � m 2 − ( m 1 ) 2 ≥ ⌊ m 1 ⌋⌈ m 1 ⌉ � � m = ( m 1 , m 2 ) is realizable ⇒ Case n = 2: (K., Lebowitz, Speer 2009) m 1 > 0 ; m 2 − ( m 1 ) 2 ≥ ⌊ m 1 ⌋⌈ m 1 ⌉ � � � � m = ( m 1 , m 2 ) is realizable ⇔ or m 1 = 0 and m 2 = 0 Kwerel 1975, Prekopa et al. 1986: K = { 0 , 1 , . . . , N } some explicit (necessary) conditions for n = 2 , 3 but no explicit conditions for n ≥ 4. T. Kuna On truncated discrete moment problems

  12. m dependent conditions We partition the set of all m : = ( m 1 , . . . , m n ) ∈ R n realizable on N 0 into: (i) m : = ( m 1 , . . . , m n ) is B-realisable if n � ∃ p ∈ P k with L m ( p ) = 0 k = 1 (ii) otherwise m is I -realisable , i.e. n � ∀ p ∈ P k one has L m ( p ) > 0 k = 1 Main Theorem (Infusino, K., Lebowitz, Speer, 2017) Let m : = ( m 1 , . . . , m n ) ∈ R n . If ( m 1 , . . . , m n − 1 ) is I-realisable, then ∃ p ( n ) ∈ P n s.t. p ( n ) does not m m depend on m n L m ( q ) ≥ L m ( p ( n ) ∀ q ∈ P n m ) , We call such a p ( n ) a minimizing polynomial for m . m Challenge: How to find p ( n ) m T. Kuna On truncated discrete moment problems

  13. Finding p ( 2 ) m : case n = 2 Let m = ( m 1 , m 2 ) ∈ R 2 be such that m 1 is I-realisable, i.e. m 1 > 0. � � P 2 : = t k ( x ) : = ( x − k )( x − k − 1 ) | k ∈ N 0 Case n = 2, m 1 > 0 � � ⇔ m 2 − ( m 1 ) 2 ≥ ⌊ m 1 ⌋⌈ m 1 ⌉ ( m 1 , m 2 ) realisable on N 0 Case: n=2 P ( 2 ) � �� � m ( x ) = x − k x − ( k + 1 ) for k = ⌊ m 1 ⌋ corresponds to condition m 2 − ( m 1 ) 2 ≥ ⌊ m 1 ⌋⌈ m 1 ⌉ . Connection to Stieltjes TMP Case n = 2, m 1 > 0 � � � � 1 m 1 � � � ≥ 0 ⇔ m 2 − m 2 ( m 1 , m 2 ) realisable on [ 0 , + ∞ ) ⇔ 1 ≥ 0 � � m 1 m 2 � T. Kuna On truncated discrete moment problems

  14. Connection between N 0 − TMP & [ 0 , + ∞ ) − TMP Let m = ( m 1 , . . . , m n − 1 , m n ) ∈ R n s.t. ( m 1 , . . . , m n − 1 ) is I-realizable on N 0 ⇓ ( m 1 , . . . , m n − 1 ) is I-realizable on [ 0 , + ∞ ) m n ∈ R s.t. ˆ m : = ( m 1 , . . . , m n − 1 , ˆ m n ) is realizable on [ 0 , + ∞ ) Take the smallest ˆ Curto-Fialkow 1991 ⇓ m is B-realizable on [ 0 , + ∞ ) ˆ m has a unique [ 0 , + ∞ ) − representing probability ν ˆ the support of ν is given by the zeros of a polynomial determined only by ( m 1 , . . . , m n − 1 ) . n = 2 : supp ( ν ) = { m 1 } n = 3 : supp ( ν ) = { 0 , m 2 / m 1 } zeros of p ( 2 ) n = 2 : supp ( ν ) = { m 1 } , m = {⌊ m 1 ⌋ , ⌊ m 1 ⌋ + 1 } ; zeros of p ( 2 ) supp ( ν ) = { 0 , m 2 / m 1 } , m = { 0 , ⌊ m 2 / m 1 ⌋ , ⌊ m 2 / m 1 ⌋ + 1 } . n = 3 : Conjecture The zeros of p ( n ) are the nearest integers to the points in supp ( ν ) m T. Kuna On truncated discrete moment problems True for n = 2 , 3 but false for n ≥ 4 !

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