SLIDE 34 Superpositioning
Given A =
⎡ ⎢ ⎢ ⎣ A(1)(1, :)
A(1)(2, :)
⎤ ⎥ ⎥ ⎦ ⊙ ⎡ ⎢ ⎢ ⎣ A(2)(:, :, 1)
A(2)(:, :, 2)
⎤ ⎥ ⎥ ⎦ ⊙ · · · ⊙ ⎡ ⎢ ⎢ ⎣ A(d−1)(:, :, 1)
A(d−1)(:, :, 2)
⎤ ⎥ ⎥ ⎦ ⊙ ⎡ ⎢ ⎢ ⎣ A(d)(:, 1)
A(d)(:, 2)
⎤ ⎥ ⎥ ⎦
B =
⎡ ⎢ ⎢ ⎣ B(1)(1, :)
B(1)(2, :)
⎤ ⎥ ⎥ ⎦ ⊙ ⎡ ⎢ ⎢ ⎣ B(2)(:, :, 1)
B(2)(:, :, 2)
⎤ ⎥ ⎥ ⎦ ⊙ · · · ⊙ ⎡ ⎢ ⎢ ⎣ B(d−1)(:, :, 1)
B(d−1)(:, :, 2)
⎤ ⎥ ⎥ ⎦ ⊙ ⎡ ⎢ ⎢ ⎣ B(d)(:, 1)
B(d)(:, 2)
⎤ ⎥ ⎥ ⎦
find C =
⎡ ⎢ ⎢ ⎣ C(1)(1, :)
C(1)(2, :)
⎤ ⎥ ⎥ ⎦ ⊙ ⎡ ⎢ ⎢ ⎣ C(2)(:, :, 1)
C(2)(:, :, 2)
⎤ ⎥ ⎥ ⎦ ⊙ · · · ⊙ ⎡ ⎢ ⎢ ⎣ C(d−1)(:, :, 1)
C(d−1)(:, :, 2)
⎤ ⎥ ⎥ ⎦ ⊙ ⎡ ⎢ ⎢ ⎣ C(d)(:, 1)
C(d)(:, 2)
⎤ ⎥ ⎥ ⎦
so that (A + B) − C F = min Something better that alternating least squares?