Long Title Your Name Joint work with X (from here), Y (from here) - - PowerPoint PPT Presentation
Long Title Your Name Joint work with X (from here), Y (from here) - - PowerPoint PPT Presentation
Long Title Your Name Joint work with X (from here), Y (from here) and Z (from here) Outline 1 Section 1 2 Section 2 3 Section 3 4 Section 4 Your Name (Durham) Short Title 29 July 2010 2 / 14 Section 1 Your Name (Durham) Short Title 29
Outline
1 Section 1 2 Section 2 3 Section 3 4 Section 4
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Section 1
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Frame Title
−ε∆u + b · ∇u = f in Ω ⊂ Rd u = 0
- n ∂Ω
Look at these equations...
Theorem
A Theorem −1 2∇ · b ≥ ρ ≥ 0.
Proof.
A Proof
- Your Name (Durham)
Short Title 29 July 2010 4 / 14
Frame Title
There are some pictures below...
(a) ε = 0.1 (b) ε = 0.01 (c) ε = 0.001
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Another Frame
Some equations and pictures... −0.01∆u + (−1, 0)⊤ · ∇u = 1 in Ω ⊂ Rd u = 0
- n ∂Ω
0.2 0.4 0.6 0.8 1 0 0.2 0.4 0.6 0.8 1 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1
(a) Standard plot
0.2 0.4 0.6 0.8 1 0.2 0.4 0.6 0.8 1 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1
(b) Temperature map
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Section 2
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Frame Title
A definition...
Definition (Something to Define)
Some text... Bε(uh, v) := ε(∇uh, ∇v) + (b.∇uh, v) = (f, v) ∀v ∈ Vh.
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more?
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Section 3
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listing things... Γ the union of boundary faces (those in ∂Ω). For e ∈ Eo
h, T + is the downwind cell, T − the upwind cell as
determined by b · n on the face from each cell, n being the outward pointing normal. For e ∈ Eo
h the jump
[ · ℄ and average {{·} } are defined by
[ν ℄ = ν+n+ + ν−n−, [τ ℄ = τ + · n+ + τ − · n−{ {ν} } = 1 2(ν+ + ν−), { {τ} } = 1 2(τ + + τ −). On the boundary these become
[ν ℄ = νn,{ {ν} } = ν, { {τ} } = τ. A very useful identity
- T∈Th
- ∂T
ντ · n =
- e∈Eh
{τ} } +
- e∈Eo
h
{ {ν} }
[τ ℄Your Name (Durham) Short Title 29 July 2010 11 / 14
Section 4
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Future work on...
Idea 1. Idea 2. Idea 3. Extra info...
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References
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