EPR = ER and Scattering Shigenori Seki Research Institute for - - PowerPoint PPT Presentation

epr er and scattering
SMART_READER_LITE
LIVE PREVIEW

EPR = ER and Scattering Shigenori Seki Research Institute for - - PowerPoint PPT Presentation

EPR = ER and Scattering Shigenori Seki Research Institute for Natural Science, Hanyang University This talk is based on the work: EPR = ER, Scattering Amplitude and Entanglement Entropy Change, Shigenori Seki and Sang-Jin Sin,


slide-1
SLIDE 1

EPR = ER and Scattering

Shigenori Seki

  • Research Institute for Natural Science, Hanyang University
  • This talk is based on the work:

“EPR = ER, Scattering Amplitude and Entanglement Entropy Change,” Shigenori Seki and Sang-Jin Sin, Phys. Lett. B735 (2014) 272. at YITP , Kyoto on 9 May 2014

1

slide-2
SLIDE 2

EPR = ER conjecture

2

slide-3
SLIDE 3

EPR pair

Einstein-Podolsky-Rosen pair [Einstein-Podolsky-Rosen, Phys.Rev. 47 (1935) 777] A B entangled two particles e.g. a spin-0 particle decays to two spin-1/2 particles. A B Separate them from each other at long distance A and B are still entangled. |Ψ⇧ = 1 ⌃ 2 (|⇤⇧A ⇥ |⌅⇧B |⌅⇧A ⇥ |⇤⇧B) (If the state of A is observed, then the one of B is determined.) SA = −tr(ρA log ρA) = log 2

3

slide-4
SLIDE 4

EPR = ER conjecture

[Maldacena-Susskind, Fortsch.Phys. 61 (2013) 781] entangled two particles A B ER bridge (or wormhole) entanglement two entangled systems are connected by ER bridge geometric interpretation Quantum mechanics Gravity A B Separate them from each other at long distance

4

slide-5
SLIDE 5
  • Accelerating quark and anti-quark



 [Jensen-Karch, Phys.Rev.Lett. 111 (2013) 211602]

  • Scattering gluons



 [SS-Sin, Phys.Lett. B735 (2014) 272] From the viewpoint of AdS/CFT correspondence, let us see two examples supporting the EPR = ER conjecture.

5

Entanglement Wormhole on world-sheet

slide-6
SLIDE 6

Accelerating quark and anti-quark

6

slide-7
SLIDE 7

! ! World!volume!horizons! anti2quark! quark!

The holographic surface of accelerating quark and anti-quark [Xiao, Phys.Lett. B 665 (2008) 173] t x z

7

x2 = t2 + b2 − z2 ds2 = 1 z2 (−dt2 + dx2 + dz2) AdS bulk metric Minimal surface

slide-8
SLIDE 8

ds2

ws =

1 σ2(τ 2 + b2 − σ2) ⇥ −(b2 − σ2)dτ 2 + (τ 2 + b2)dσ2 − 2τσdτdσ ⇤ t = τ, z = σ Static gauge World-sheet induced metric

8

[Jensen-Karch, Phys.Rev.Lett. 111 (2013) 211602] The quark and anti-quark are entangled by the wormhole that the open string goes through. The trajectories of quark and anti-quark are causally disconnected on the world-sheet.

t x z

x2 = t2 (z = b) x2 = t2 + b2 (z = 0) wormhole

slide-9
SLIDE 9

Are other interacting particles also related to a wormhole on world-sheet? The entanglement of quark and anti-quark (EPR pair) The interaction between quark and anti-quark ER bridge (wormhole)

  • n world-sheet

Fortunately, we know the minimal surface in AdS that describes a gluon-gluon scattering.

9

We can naturally guess that the entanglement of final states is different from that of initial states due to interaction. Therefore the scattering process induces the entanglement entropy change.

slide-10
SLIDE 10

Scattering gluons

10

slide-11
SLIDE 11

Minimal surface solution for gluon scattering

[Alday-Maldacena, JHEP 0706 (2007) 064] ds2 = R2 r2 (ηµνdyµdyν + dr2) AdS5 (momentum space) ∆yµ = 2πkµ IR boundary condition r = 0 y0 = α

  • 1 + β2 sinh u1 sinh u2

cosh u1 cosh u2 + β sinh u1 sinh u2 , y1 = α sinh u1 cosh u2 cosh u1 cosh u2 + β sinh u1 sinh u2 , y2 = α cosh u1 sinh u2 cosh u1 cosh u2 + β sinh u1 sinh u2 , y3 = 0 , r = α cosh u1 cosh u2 + β sinh u1 sinh u2 , −s(2π)2 = 8α2 (1 − β)2 , −t(2π)2 = 8α2 (1 + β)2 . The solution of Nambu-Goto action Mandelstam variables:

11

1

2

3

4

slide-12
SLIDE 12

AdS5 (position space) AdS5 (momentum space) ds2 = R2 z2 (ηµνdxµdxν + dz2) “T-dual” transformation: ⇥myµ = R2 z2 mn⇥nxµ , z = R2 r x0 = −R2 2α p 1 + β2 sinh u+ sinh u− , x+ := x1 + x2 √ 2 = − R2 2 √ 2α [(1 + β)u− + (1 − β) cosh u+ sinh u−] , x− := x1 − x2 √ 2 = R2 2 √ 2α [(1 − β)u+ + (1 + β) sinh u+ cosh u−] , x3 = 0 , z = R2 2α [(1 + β) cosh u+ + (1 − β) cosh u−] u± := u1 ± u2 where . For later convenience, we introduce The Alday-Maldacena solution is mapped to Xµ := α R2 xµ (µ = 0, +, −, 3) , Z := α R2 z (≥ 1)

12

[Kallosh-Tseytlin, JHEP 9810 (1098) 016]

slide-13
SLIDE 13

Causal structure on world-sheet

The induced metric on world-sheet g++ = 4(1 + β)2 sinh2 u+ + 4(1 + β2) − [(1 + β) cosh u+ − (1 − β) cosh u−]2 2 [(1 + β) cosh u+ + (1 − β) cosh u−]2 , g+− = 2(1 − β2) sinh u+ sinh u− [(1 + β) cosh u+ + (1 − β) cosh u−]2 , g−− = 4(1 − β)2 sinh2 u− + 4(1 + β2) − [(1 + β) cosh u+ − (1 − β) cosh u−]2 2 [(1 + β) cosh u+ + (1 − β) cosh u−]2 . “Horizons” ds2

ws = R2

g++du2

+ + 2g+−du+du− + g−−du2 −

  • g++ = 0 :

(1 − β) cosh u− = (1 + β) cosh u+ + 2 q (1 + β)2 sinh2 u+ + 1 + β2 g−− = 0 : (1 + β) cosh u+ = (1 − β) cosh u− + 2 q (1 − β)2 sinh2 u− + 1 + β2 [SS-Sin, Phys.Lett. B735 (2014) 272]

13

slide-14
SLIDE 14

0 ≤ β < 1

10 5 5 10 10 5 5 10 1.0 0.5 0.5 1.0 1.0 0.5 0.5 1.0

β = 0 β = 1/2 ˆ X± := 2 π arctan X± ∈ [−1, 1] X± ∈ (−∞, +∞)

10 5 5 10 10 5 5 10 1.0 0.5 0.5 1.0 1.0 0.5 0.5 1.0

Z = ∞ Z = 1 14

thick red: , dashed red: , dotted blue:

  • blue & red: constant

green: constant g++ = 0 g−− = 0 g++ = g−− Z X0

slide-15
SLIDE 15

β = 1 Regge limit: with fixed. −s → ∞ −t X0 = − 1 √ 2 sinh u+ sinh u− , X+ = − 1 √ 2u− , X− = 1 √ 2 sinh u+ cosh u− , X3 = 0 , Z = cosh u+ .

1.0 0.5 0.5 1.0 1.0 0.5 0.5 1.0 10 5 5 10 10 5 5 10

15

While is positive definite, vanishes on . g++ g−− cosh u+ = √ 2

slide-16
SLIDE 16

EPR = ER in gluon scattering?

Incoming gluons: Outgoing gluons:

1.0 0.5 0.5 1.0 1.0 0.5 0.5 1.0

|g1(t1)i i = X

i,j

c(1)

ij |ALi(t1)i ⌦ |ARj(t1)i

|g2(t1)i i = X

i,j

c(2)

ij |BLi(t1)i ⌦ |BRj(t1)i

|g3(t2)i i = X

i,j

c(3)

ij |ALi(t2)i ⌦ |BRj(t2)i

|g4(t2)i i = X

i,j

c(4)

ij |BLi(t2)i ⌦ |ARj(t2)i

16

We can see two types of entanglement which are interpreted to wormholes. {g1, g2} → {g3, g4}

slide-17
SLIDE 17

0.5 1.0

  • 1. Internal entanglement

The open string endpoints in each gluon are entangled by the open string going through the wormhole. This is in the same way as the entanglement of quark and anti-quark. |g1(t1)i i = X

i,j

c(1)

ij |ALi(t1)i ⌦ |ARj(t1)i

17

slide-18
SLIDE 18
  • 2. Entanglement of gluons

1.0 0.5 0.5 1.0 1.0 0.5 0.5 1.0 1.0 0.5 0.5 1.0 1.0 0.5 0.5 1.0

There are two channels.

18

1.0 0.5 0.5 1.0 1.0 0.5 0.5 1.0

Any paths connecting the gluons must go through the wormhole region.

slide-19
SLIDE 19

2αz∞ R2 = (1 + β) cosh u+∞ + 1 − β = (1 − β) cosh u−∞ + 1 + β ⇥+() = R Z +u+∞

−u+∞

du+ √g++

  • u−=0 ,

⇥−() = R Z +u−∞

−u−∞

du− √g−−

  • u+=0

How can we measure the change of entanglement in gluon scattering process? i ) (naively) log of scattering amplitude ii) the length between boundaries at the contacting points ⇤±(⇥) = R √ 6 log 2z∞ R2 + √ 6 log 1 1 ± ⇥ + O ✓ 1 z∞ ◆ where we introduced the cutoff, . z∞ (→ ∞) ∆S ∼ (`+() − `−())2

19

diverges at the Regge limit, , and vanishes at . β = 1 β = 0 ∆S The scattering amplitude corresponds to the Wilson loop which is given by the area of minimal surface. And naively . S = (1 n∂n) loghWi|n→1 A ∼ e−Area, ∆S ∼ log A = √ λ 2π ✓ log 1 + β 1 − β ◆2 s t = ✓1 + β 1 − β ◆2 [Lewkowycz-Maldacena, JHEP 1405 (2014) 025]

slide-20
SLIDE 20

Scattering vs Entanglement Scattering process S-matrix {p1, p2} → {k1, k2} |inii = |p1, p2i |fini = X

ki

|k1, k2ihk1, k2|S|inii The entanglement of particles is changed from the initial state to the final one. Problem: we need to understand the relation between S-matrix theory and entanglement entropy both in the quantum field theory directly and in holography.

20

ei(H0+Hint)t