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Business Statistics CONTENTS Post-hoc analysis ANOVA for 2 groups - - PowerPoint PPT Presentation

SEVERAL S AND MEDIANS: MORE ISSUES Business Statistics CONTENTS Post-hoc analysis ANOVA for 2 groups The equal variances assumption The Kruskal-Wallis test Old exam question Further study POST-HOC ANALYSIS After rejecting the null


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SEVERAL 𝜈S AND MEDIANS: MORE ISSUES

Business Statistics

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Post-hoc analysis ANOVA for 2 groups The equal variances assumption The Kruskal-Wallis test Old exam question Further study CONTENTS

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After rejecting the null hypothesis of equal means, we naturally want to know: β–ͺ which of the means differ (differs) significantly? β–ͺ is it (are they) lower or higher than the others? We are only allowed to go into this after 𝐼0 has been rejected β–ͺ therefore, we speak of a post-hoc analysis or post-hoc test For 𝑑 groups, there are

𝑑 π‘‘βˆ’1 2

distinct pairs of means to be compared β–ͺ so-called multiple comparison tests POST-HOC ANALYSIS

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There are many such multiple comparison tests We focus on Tukey’s studentized range test (or HSD for β€œhonestly significant difference” test) β–ͺ a multiple comparison test that is widely used β–ͺ named after statistician John Wilder Tukey (1915-2000) POST-HOC ANALYSIS

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POST-HOC ANALYSIS

This line, for instance, compares Club 1 to Club 3

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On the basis of significant differences, SPSS defines homogeneous subsets Rule: if two groups are in the same subset, they do not differ significantly POST-HOC ANALYSIS

The means of club 2 and club 3 cannot be discerned (statistically), and both differ significantly from the mean of club 1. And: club 1 is significantly better.

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Comparing 2 means β–ͺ Choice between:

β–ͺ independent sample 𝑒-test β–ͺ ANOVA

β–ͺ Example on Computer Anxiety Rating ANOVA FOR 2 GROUPS

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Result of 𝑒-test (which of the two?) Result of ANOVA ANOVA FOR 2 GROUPS

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Comparing two means (equality: 𝜈1 = 𝜈2) β–ͺ 𝑒-test

β–ͺ null distribution: 𝑒~π‘’π‘œ1+π‘œ2βˆ’2 β–ͺ reject for small and large values β–ͺ equal variance required β–ͺ or the other test without this requirement β–ͺ normal populations required β–ͺ or symmetric populations and π‘œ1, π‘œ2 β‰₯ 15, or π‘œ1, π‘œ2 β‰₯ 30

β–ͺ ANOVA for two groups (one factor with two levels)

β–ͺ null distribution 𝐺~𝐺

1,π‘œ1+π‘œ2βˆ’2

β–ͺ reject for large values β–ͺ equal variance required β–ͺ normal populations required

ANOVA FOR 2 GROUPS

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So, 𝑒-test is not superfluous now we have ANOVA You still need the independent samples 𝑒-test: β–ͺ more hypotheses possible (𝜈1 β‰₯ 𝜈2, 𝜈1 = 𝜈2 + 7, etc.) β–ͺ weaker requirement for population variances β–ͺ weaker requirement for population distributions ANOVA FOR 2 GROUPS

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Main assumption of ANOVA: equal variances Seen before in the independent samples 𝑒-test β–ͺ where the pooled variance was used to estimate 𝜏1

2 = 𝜏2 2

the assumption was tested with Levene’s test THE EQUAL VARIANCES ASSUMPTION

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Levene’s test is a homogeneity of variance test β–ͺ works for two variances (H0: 𝜏1

2 = 𝜏2 2)

β–ͺ but also for several variances (H0: 𝜏1

2 = 𝜏2 2 = 𝜏3 2 = β‹―)

Example (golf clubs) β–ͺ π‘žβˆ’value ≫ 0.1, so hypothesis of equal variances is not rejected β–ͺ validity of use of ANOVA is OK THE EQUAL VARIANCES ASSUMPTION

if not, escape to nonparametric ANOVA? see next ...

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β–ͺ Recall that we used non-parametric methods when populations are not normally distributed

β–ͺ Can we develop a non-parametric ANOVA?

β–ͺ Yes: the Kruskal-Wallis test

β–ͺ based on ranking of the observations on 𝑍 β–ͺ compares medians (𝐼0: 𝑁1 = 𝑁2 = 𝑁3 = β‹―) β–ͺ has lower power than ANOVA (is less sensitive) β–ͺ requires few assumptions

β–ͺ Generalization of Wilcoxon-Mann-Whitney test, but for more than two groups THE KRUSKAL-WALLIS TEST

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Computational steps in Kruskal-Wallis test: β–ͺ Rank the observations 𝑧1, … , π‘§π‘œ, yielding 𝑠

1, … , 𝑠 π‘œ

β–ͺ π‘œπ‘˜ size of group π‘˜; π‘œ = Οƒπ‘˜=1

𝑑

π‘œπ‘˜

β–ͺ Calculate the sum of ranks in every group

β–ͺ π‘ˆ

π‘˜ = σ𝑗=1 π‘œπ‘˜ π‘†π‘—π‘˜ (for all groups π‘˜ = 1, … , 𝑑)

β–ͺ Calculate test statistic

β–ͺ 𝐼 =

12 π‘œ π‘œ+1 Οƒπ‘˜=1 𝑑

π‘œπ‘˜ π‘ˆβˆ™π‘˜ βˆ’ ന π‘ˆ

βˆ™βˆ™ 2 ; reject for large values

β–ͺ Under 𝐼0: 𝐼 ∼ πœ“π‘‘βˆ’1

2

β–ͺ test right-tailed (like ANOVA) β–ͺ for very small samples (groups<5), test not appropriate

THE KRUSKAL-WALLIS TEST

Required: populations of β€œsimilar” shape On formula sheet a slightly different form that works easier

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Example: comparing three golf clubs β–ͺ using SPSS THE KRUSKAL-WALLIS TEST

π‘ž-value Kruskal-Wallis statistic (𝐼)

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Fill out the table EXERCISE 1

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21 May 2015, Q1n OLD EXAM QUESTION

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Doane & Seward 5/E 11.3-11.4, 16.5 Tutorial exercises week 4 Homogeneous subsets, Kruskal-Wallis test FURTHER STUDY